Question

Given: EFGH inscribed in k(O) m∠FHE = 45°, m∠EGH = 49° Find: m∠FEH

Answer 1

Answer:

$m$

Step-by-step explanation:

we know that

The inscribed angle measures half that of the arc comprising

step 1

Find the measure of arc EF

$m$

we have

$m$

substitute

$45\°=\frac{1}{2}(arc\ EF)$

$arc\ EF=90\°$

step 2

Find the measure of arc EH

$m$

we have

$m$

substitute

$49\°=\frac{1}{2}(arc\ EH)$

$arc\ EH=98\°$

step 3

Find the measure of arc FGH

$arc\ FGH=360\°-(arc\ EH+arc\ EF)$

substitute the values

$arc\ FGH=360\°-(98\°+90\°)$

$arc\ FGH=172\°$

step 4

Find the measure of angle FEH

$m$

we have

$arc\ FGH=172\°$

substitute

$m$