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vitfil [10]
2 years ago
5

Steve rides his bike at a rate of 1760 feet per minute. What is his rate in miles per hour?

Mathematics
1 answer:
raketka [301]2 years ago
4 0

Answer:

<h2>The answer is  19.36 miles per hours</h2>

Step-by-step explanation:

this problem is a unit conversion problem

In this problem, we are expected to convert from feet/min to miles per hour

given that the rate is 1760 feet per minute

from tables, we are given that

1 foot per minute is  0.011 miles per hour hence

1760 feet per minutes will give x miles per hour

cross multiplying we have

x= 1760*0.011

x= 19.36 miles per hours

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What is 6 divided by 612
kondaur [170]
612/6=102
check: 6x102=612

Hope this helped! :))
8 0
2 years ago
Read 2 more answers
"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r
sergiy2304 [10]

Answer:

(a) Null Hypothesis, H_0 : p_1-p_2=0  or  p_1= p_2  

    Alternate Hypothesis, H_A : p_1-p_2\neq 0  or  p_1\neq p_2

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

<em />

<em>Let </em>p_1<em> = proportion of drivers that were in compliance initially</em>

p_2<em> = proportion of drivers that were in compliance one year later</em>

(a) <u>Null Hypothesis</u>, H_0 : p_1-p_2=0  or  p_1= p_2      {means that there is not any statistical difference in these two proportions measured initially and then one year later}

<u>Alternate Hypothesis</u>, H_A : p_1-p_2\neq 0  or  p_1\neq p_2     {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is <u>Two-sample z proportion statistics</u>;

                     T.S.  = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of drivers in compliance initially = 98.9%

\hat p_2 = sample proportion of drivers in compliance one year later = 96.9%

n_1 = sample of drivers initially = 1,250

n_2 = sample of drivers one year later = 1,100

(b) So, <u><em>the test statistics</em></u>  =  \frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }  

                                           =  3.33

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 3.33) = 1 - P(Z \leq 3.33)

                                            = 1 - 0.99957 = <u>0.00043</u>

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis.</em></u>

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

7 0
2 years ago
Jed entered the following values into the TVM Solver on his graphing calculator.
Elden [556K]

Answer: 17.7

Step-by-step explanation:

69/ 3.9%•100= 17.69= 17.7

8 0
2 years ago
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Initially, there were only 197 weeds at a park. The weeds grew at a rate of 25% each week. The following function represents the
Anarel [89]

Answer:

  D.)  f(x) = 197(1.03)^(7x); grows at a rate of approximately 3% daily

Step-by-step explanation:

The growth equation can be written in terms of a rate compounded 7 times per week:

  f(x) = 197×1.25^x = 197×(1.25^(1/7))^(7x)

  f(x) ≈ 197×1.0324^(7x) . . . . x represents weeks, a daily growth factor is shown

The daily growth rate as a percentage is the difference between the daily growth factor and 1, expressed as a percentage:

  (1.0324 -1) × 100% = 3.24%

The best match is choice D:

  f(x) ≈ 197(1.03^(7x)); grows approximately 3% daily

4 0
2 years ago
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Mike watches a caterpillar climbing on a tree trunk he writes the expression -5/8-(-1/8-1/2) to show the change in feet of the c
guapka [62]

Answer:

-5 / 8 - -4 / 8 equals the approximate estimate notation of 58.7

7 0
2 years ago
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