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malfutka [58]
2 years ago
7

In a research report, Richard H. Weindruch of the UCLA medical school claims that mice with an average lifespan of 32 months wil

l live to be about 40 months old when 40% of the calories in their diet are replaced by vitamins and protein (take the null hypothesis to be µ = 40 months). Is there any reason to believe that mice live, on average, less than 40 months if 64 mice that are placed on this diet have an average life of 38 months, assuming a population standard deviation of 5.8 months?
Mathematics
1 answer:
xenn [34]2 years ago
8 0

Answer:

p_v =P(Z  

If we compare the p value and a significance level assumed for example \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and the the actual true mean for the average life is significant less than 40 months.  

Step-by-step explanation:

Data given and notation  

\bar X=38 represent the average life

\sigma=5.8 represent the standard deviation for the population  

n=64 sample size  

\mu_o =40 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to determine if the mean is less than 40 months, the system of hypothesis would be:  

Null hypothesis:\mu \geq 40  

Alternative hypothesis:\mu < 40  

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{38-40}{\frac{5.8}{\sqrt{64}}}=-2.759

Calculate the P-value  

Since is a one-side left tailed test the p value would be:  

p_v =P(Z  

Conclusion  

If we compare the p value and a significance level assumed for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual true mean for the average life is significant lss than 40 months.  

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2 years ago
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Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was \$43.25$43.25dollar sign, 43,
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Answer:

29 minutes

Step-by-step explanation:

Given

Total = \$43.25

Entrance\ Fee = \$7

Per\ Minute = \$1.25

Required

Determine the number of minutes (t) that he was on the trampoline.

This can be expressed as:

Total\ Payment = Entrance\ Fee + Amount\ per\ minute * t

Where t represents the number of minutes

Substitute values for Total, Entrance Fee and Amount per minute

43.25 = 7 + 1.25 * t

43.25 = 7 + 1.25t

Solving further to get the value of t, we have:

1.25t = 43.25 - 7

1.25t = 36.25

t = 36.25/1.25

t = 29

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2 years ago
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An artist wants to make alabaster pyramids using a block of alabaster with a volume of 576 cubic inches. She plans to make each
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Given:
volume of the block = 576 cubic inches
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Volume of square pyramid = a² * h/3
V = 3 square inches * 4inches/3
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volume of block / volume of square pyramid
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She can make 144 square pyramids.
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a crane cable can support a maximum load of 15,000 kg. if a bucket has a mass of 2,000 kg and gravel has a mass of 1,500 kg for
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Therefore, the crane can safely lift a maximum of 8 2/3 cubic meters of gravel.
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For quality control​ purposes, a company that manufactures sim chips for​ cell/smart phones routinely takes samples from its pro
ololo11 [35]

Answer:

There is a 22.42% probability that a sample in this size has 2 imperfections.

Step-by-step explanation:

For each chip, there are only two possible outcomes. Either they are imperfect, or they are not.

This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

A success is a chip being imperfect. Suppose the average number of imperfections per 1000 sim chips is 3. So \pi = \frac{3}{1000} = 0.003.

What is the probability that a sample this size​ (1000 chips) has 2​ imperfections?

The sample has 1000 chips, wo n = 1000

We want P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{1000,2}.(0.003)^{2}.(0.997)^{998} = 0.2242

There is a 22.42% probability that a sample in this size has 2 imperfections.

7 0
2 years ago
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