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Jobisdone [24]
1 year ago
12

Orthographic projection and isometric projection are two ways to show three-dimensional objects in a two-dimensional space, such

as on a piece of paper or a computer screen. Each method gives a different perspective. Do some research and then compare and contrast the two methods for displaying three-dimensional shapes. Then try your hand at creating both types of projections for a simple geometric shape using paper, pencil, and a ruler. In your opinion, what are the pros and cons of each projection? What are the limitations? In which circumstances, environments, or occupations is one type of projection likely preferred over the other? Describe any special tools that might be needed to create the projection. Which projection is easiest for you to interpret visually? Why?
Mathematics
1 answer:
DerKrebs [107]1 year ago
5 0

Answer:

Orthographic Projection is used for making the projects but Isometric Projection is used to have better understanding of the object.

Orthographic drawings are typically two dimensional views of an object. For instance, if you were designing a table, you would draw a top view, side view and a bottom view. Should these three views not fully explain the design of the table other views would need to be drawn. When drawing an perspective view in an orthographic manner, you would utilize a 45 degree triangle for the lines that extend back or forward from the vertical lines. This type of perspective is not a true perspective because you can measure the true length of all the details shown. An isometric drawing is meant to depict a 3D image of an object in what appears to be a perspective view. However, similar to an orthographic perspective, all of the lines in an isometric drawing can be measured to their true length. What makes it different from an orthographic perspective is that its angled lines are drawn at 30 or 60 degrees or divisions of them. Drawing this by hand you would use a 30/60/90 triangle.

In either case, both types of perspectives can be accurately measured with a ruler in order to know the objects measurements.

Step-by-step explanation:

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preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha
VladimirAG [237]

Answer:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

n=369

Step-by-step explanation:

1) Notation and definitions

X=40 number of the selected labourers opt for a new incentive scheme.

n=100 random sample taken

\hat p=\frac{40}{100}=0.4 estimated proportion of the selected labourers opt for a new incentive scheme.

p true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

And rounded up we have that n=369

8 0
1 year ago
Matthew and his 3 siblings are wedding a flower bed with an area of 9 square yards. If they shared the job equally,how much squa
Tatiana [17]
The answer is 27 yards
4 0
1 year ago
Your school wants to take out an ad in the paper congratulating the basketball team on a successful​ season, as shown to the rig
Serga [27]

Answer:

1.4in

Step-by-step explanation:

Length of Photo = 4in

Width of Photo = 3in

Unknown:

Value of X = ?

Solution:

Follow these steps:

  Area of a rectangle  = l x w

Since the photo is a rectangle; area of photo:

  Area of photo  = 4in x 3in = 12in²

For the area of the ad;

   Length of ad  = 4 + x

   Width of ad = 3 + x

Given that,

                  the area of the photo  = \frac{1}{2} area of ad

                           12in²  = \frac{1}{2} area of ad

                   Area of ad  = 24in²

Area of the ad;

             (4 + x) (3 + x)  = 24

               12 + 4x + 3x + x² = 24

                12 + 7x + x²  = 24

                       x² + 7x = 24 - 12

                       x² + 7x = 12

                     x² + 7x - 12  = 0

            Using the almighty formula where

     a  = 1, b = 7 and c = -12

          x  = \frac{-b (+/-) \sqrt{b^{2} } - 4ac}{2a}

     

          x = \frac{-7 + \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}   or \frac{-7 - \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}

          x  = 1.4  or  -8.4

therefore the answer is 1.4in

x is 1.4in

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1 year ago
Isosceles triangle LMN is graphed with vertices L(0, 1), M(3, 5), and N(6,1). What is the slope of side LN? Negative StartFracti
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Answer:

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Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
mars1129 [50]

Answer: In the beginning he was given 27 sweets.

Step-by-step explanation: The most logical thing to do is to solve it backwards, that is, from what he had at the end of the third day up till the beginning of the first day.

On the third day he ate one-third and had 8 sweets left over. To determine how many he started with on the third day, let the total on day three be called a. If one-third of a is eaten, then the left over which is two-thirds is 8. That is;

8/a = 2/3

By cross multiplication we now have

8 x 3 = 2a

24/2 = a

a = 12

Let the number of sweets he had on day two be called b. If he ate one-third of b and he had 12 left over, then the two-thirds left over is 12 and we now have;

12/b = 2/3

By cross multiplication we now have

12 x 3 = 2b

36 = 2b

36/2 = b

b = 18

Let the number of sweets he had on day one be called x. If he ate one-third of x and he had 18 left over, then the two-thirds left over is 18, and we now have;

18/x = 2/3

By cross multiplication we now have

18 x 3 = 2x

54 = 2x

x = 27

Therefore Tim was given 27 sweets at the beginning.

3 0
2 years ago
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