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andre [41]
2 years ago
6

The numbers 1-4 are each written on an index card. The 4 cards are put into a bag and 2 of them are drawn at random. What is the

probability that the sum of the two cards drawn are greater than 5? I actually know the answer to this question (1/3), however, I don’t know how to solve it; please include an explanation.
Mathematics
1 answer:
devlian [24]2 years ago
7 0

Answer:

Step-by-step explanation:

Write a list of all possible outcomes

1-2

1-3

1-4

2-1

2-3

2-4

3-1

3-2

3-4

4-1

4-2

4-3

There are 12 possible outcomes. How many of them have totals of 6 or 7

I count 4

So the probability is 4/12 = 1/3, just as you said.

Is there an easier way?

You might be able to get the 12 easier.

You have 4 choices for the first number and 3 for the second.

P(12) = 4*3 = 12

Getting 6 or 7 might be somewhat trickier.

4 and 3 make seven. That gives two ways 4-3 and 3-4

4 and 2 make six. That gives 2 more ways 4-2 and 2-4

That's all that's possible.

answer: 4 ways make success. The total number of ways is 12.

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Answer:

The following are the answer to this question:

Step-by-step explanation:

In the given question the numeric value is missing which is defined in the attached file please fine it.  

Calculating the probability of the distribution for x:

\to f(x) = 0.19\  for \ x=14\\\\\to  f(x) = 0.29 \ for\ x=7\\\\\to f(x) = 0.38\  for \ x=1\\\\\to f(x)=0.14 \ for \ x=0\\

The formula for calculating the mean value:

\bold{ E(X)= x \times f(x)}

          =14 \times 0.19+7 \times 0.29+1 \times 0.38+0\times 0.14\\\\=2.66 + 2.03+0.38+ 0\\\\=5.07

\bold{E(X^2) = x^2 \times f(x)}

           =14^2 \times 0.19+7^2 \times 0.29+1^2 \times 0.38+0^2 \times 0.14 \\\\=196 \times 0.19+ 49 \times 0.29+1 \times 0.38+0 \times 0.14\\\\= 37.24+ 14.21+ 0.38+0 \\\\=51.83

use formula for calculating the Variance:

\to \bold{\text{Variance}= E(X^2) -[E(X)]^2}

                  = 51.83 - (5.07)^2\\\\= 51.83 -  25.70\\\\=26.13

calculating the value of standard deivation:

Standard Deivation (SD) = \sqrt{Variance}

                                          = \sqrt{26.13} \\\\=5.111

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