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Viktor [21]
2 years ago
13

Which function has a simplified base of 4^3√4?

Mathematics
1 answer:
IrinaVladis [17]2 years ago
4 0

Answer:

The function is f(x) = 4(\sqrt[3]{16} )^{2x}.

Step-by-step explanation:

We have to choose from options the exponential function which has a simplified base of 4∛4 i.e. ∛(256).

Now, the exponential function in the option III will be the answer.

The function is f(x) = 4(\sqrt[3]{16} )^{2x}.

So, the base is (\sqrt[3]{16} )^{2} = \sqrt[3]{16^{2}} = \sqrt[3]{256} = 4\sqrt[3]{4}. (Answer)

The general formula of an exponential function is f(x) = a(b)^{x} , where b is called the base of the function.  

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What is m? 49° 77° 98° 161°
Mariana [72]

we know that

The measurement of <u>the external angle</u> is the semi-difference of the arcs it includes.

In this problem

21\°=\frac{1}{2}[arc\ RU-arc\ SU]

Solve for the measure of arc SU

42\°=[arc\ RU-arc\ SU]

arc\ SU=arc\ RU-42\°

arc\ SU=119\°-42\°=77\°

therefore

the answer is

The measure of the arc SU is 77\°

4 0
2 years ago
Read 2 more answers
Robert has $50 to spend on his utility bills each month. The basic monthly charge is 23.77 electricity costs 0.1117 for each kil
Lilit [14]

Answer:

<em>The maximum number of kilowatt-hours is 235</em>

Step-by-step explanation:

<u>Inequalities</u>

Robert's monthly utility budget is represented by the inequality:

0.1116x + 23.77 < 50

Where x is the number of kilowatts of electricity used.

We are required to find the maximum number of kilowatts-hours used without going over the monthly budget. Solve the above inequality:

0.1116x + 23.77 < 50

Subtracting 23.77:

0.1116x < 50 - 23.77

0.1116x < 26.23

Dividing by 0.1116:

x < 26.23/0.1116

x < 235

The maximum number of kilowatt-hours is 235

7 0
1 year ago
A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like
mixas84 [53]

Answer:

a) \mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) \mathbf{x = 2000 - 2000e^{-0.015t}}

c)  the  steady state mass of the drug is 2000 mg

d) t ≅ 153.51  minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

Rate _{(in)}= 500 \ mg/L  \times 0.06 \  L/min = 30 mg/min

Rate _{(out)}=\dfrac{x}{4} \ mg/L  \times 0.06 \  L/min = 0.015x \  mg/min

Therefore;

\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}

with respect to  x(0) = 0

\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

\dfrac{dx}{dt} = -0.015(x - 2000)

\dfrac{dx}{(x - 2000)} = -0.015 \times dt

By Using Integration Method:

ln(x - 2000) = -0.015t + C

x -2000 = Ce^{(-0.015t)

x = 2000 + Ce^{(-0.015t)}

However; if x(0) = 0 ;

Then

C = -2000

Therefore

\mathbf{x = 2000 - 2000e^{-0.015t}}

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}

x = 2000 - 0

x = 2000

Thus; the  steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}

0.1 = e^{(-0.015t)

ln(0.1) = -0.015t

t = -\dfrac{In(0.1)}{0.015}

t = 153.5056729

t ≅ 153.51  minutes

4 0
2 years ago
In circle E, and are diameters. Angle BCA measures 53°. Circle E is shown. Line segments A C and B D are diameters. Lines are dr
yuradex [85]

Answer:

74

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Calculate δe, if q= 0.764 kj and w= -830 j . express your answer using two significant figures.
Deffense [45]
Given:
Q = 0.0764 kJ = 764 J, heat input
W = -830 J, useful work done

From the 1st Law of Thermodynamics, the change in internal energy is
δE = Q - W
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     =  1594 J = 1.594 kJ

Answer: 1.59 kJ (two sig. fig.)
8 0
2 years ago
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