3. Who set up their equation correctly for the following question?

the letters that spell Mississippi are each written on separate tiles lying face down on a table. a tile is selected at random,

Mars2501 [29]

Answer: The theoretical probability of choosing a tile with letter P =0.18

Step-by-step explanation:

Given word = MISSISSIPPI

Total number of letters in given the word = 11

Number of letter P in given word = 2

Let A be a event of choosing a tile with a letter P then

P(A) =Number of tiles with letter P / Total letters in given word

= 2 /11 = 0.18

6 0

1 year ago

Please help me asap! Could you please explain how you got the answer

svetoff [14.1K]

Answer:

B) 23

Step-by-step explanation:

Table: Algebra | No algebra | Total

Physics | 4 Step 1: 8 12

No physics |Step 2: 15

Total | 19 30

We look for the number of people who are in algebra and no physics or physics and no algebra.

1. 12 - 4 = 8

2. 19 - 4 = 15

3. We find the total of those numbers: 15 + 8 = 23

7 0

2 years ago

"The Highest Common Factor (HCF) of my two numbers is 3 The Lowest Common Multiple (LCM) of my two numbers is 45" (b) Write down

Mila [183]

Answer:

Step-by-step explanation:

15 and 3

6 0

2 years ago

Amy hiked 3.25 miles farther than Meng. Amy hiked 7 miles. Which equation can be used to find the number of miles, x, Meng hiked

Verdich [7]

Let distance covered by Meng be 'x' (given)

x+3.25=7

5 0

2 years ago

Read 2 more answers

Find the area of the part of the plane 5x + 4y + z = 20 that lies in the first octant.

BlackZzzverrR [31]

This part of the plane is a triangle. Call it $\mathcal S$ . We can find the intercepts by setting two variables to 0 simultaneously; we'd find, for instance, that $y=z=0$ means $5x=20\implies x=4$ , so that (4, 0, 0) is one vertex of the triangle. Similarly, we'd find that (0, 5, 0) and (0, 0, 20) are the other two vertices.

Next, we can parameterize the surface by

$\mathbf s(u,v)=\langle4(1-u)(1-v),5u(1-v),20v\rangle$

so that the surface element is

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=20\sqrt{42}(1-v)\,\mathrm du\,\mathrm dv$

Then the area of $\mathcal S$ is given by the surface integral

$\displaystyle\iint_{\mathcal S}\mathrm dS=20\sqrt{42}\int_{u=0}^{u=1}\int_{v=0}^{v=1}(1-v)\,\mathrm dv\,\mathrm du$
$\displaystyle=20\sqrt{42}\int_{v=0}^{v=1}(1-v)\,\mathrm dv=10\sqrt{42}\approx64.8074$

3 0

2 years ago