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AlexFokin [52]
2 years ago
6

Khalid and Jesse took different overnight trains. The graph shows the relationship between the total distance Khalid traveled an

d the time in hours. The distance Jesse traveled after x hours is given by the equation y = 150x. Who, if anyone, traveled at a faster speed? Use the drop-down menus to explain your answer.
Mathematics
1 answer:
Usimov [2.4K]2 years ago
4 0

Answer:

Jesse - 150 miles per hour.

Step-by-step explanation:

On the graph, it shows that the rise is 140 and the run is 1. 140/1 is 140, making the slope for Khalid is 140. The equation (y = 150x) shows that the slope is 150 (y = mx). Since 150 is greater than (>) 140, Jesse's train is more faster than Khalid since she is moving at 150mph rather than 140mph.

Also, is this for Pearson Realize?

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Answer:

(x - 5)(x + 2)

Step-by-step explanation:

x² - 3x - 10 =

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2 years ago
An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
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Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

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2 years ago
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Step-by-step explanation:

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Answer:

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Answer:

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So m(x) = 20,000(0.97)^x   (answer).

7 0
2 years ago
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