Answer:
- Listing of 15 students
- Assignment of a sequential number to each student.
- The figured out sample size, i.e., 2.
- Selected sample using sampling frame 15 from Step 2 and your sample size from Step 3, i.e., 2
Step-by-step explanation:
Random sampling is a piece of the sampling method where each example has an equivalent likelihood of being picked. An example picked randomly is intended to be an impartial portrayal of the all out populace. On the off chance that for certain reasons, the example doesn't speak to the populace, the variety is known as a sampling mistake. A random example is an example that is picked randomly. It could be all the more precisely called a randomly picked test. Random examples are utilized to stay away from inclination and other undesirable impacts. Random sampling is probably the least complex type of gathering information from the all out populace. Under random sampling, every individual from the subset conveys an equivalent chance of being picked as a piece of the sampling procedure.
<h2>
Answer:</h2>
The graph is shown in the Figure below
<h2>
Step-by-step explanation:</h2>
In this exercise, we have an equation. On the left side we have a straight line with slope 
and there is no any y-intercept. On the right side, on the other had, we also have a straight line, but the slope here is 
. Therefore, by plotting these two straight lines, we have that the solution is the origin, that is, the point 
.
Answer:
7
Step-by-step explanation:
5×0.4 = 2
2 + 5 = 7
Two triangles are similar if all corresponding sides are proportional.
Therefore, if it is given that sides are proportional, then the two triangles are similar.
This property of triangles is consistent and either true or false so sometimes is never an answer.
Since it is true , the answer is Always.
Answer:
- a)
- b)
- c)
- d)
Step-by-step explanation:
We will use the product rule from combinatorics.
- a) There are 26 letters in the English alphabet, so there are 26 possible choices for the first character and 26 possible choices for the last one. Each one of the remaining eight characters of the string has 36 choices (letters or digits). By the product rule, there are
strings.
- b) We have 5 possible choices for the first character, it must be some vowel a,e,i,o,u. The second character can be chosen in 21 ways, selecting some consonant. There are 10 possibilities for the last character because only of the digits are allowed. The other seven characters have no restrictions, so each one can be chosen in 36 ways. By the product rule there are
strings.
- c) The third character has 5 possibilities. Repetition of vowels is allowed, so the sixth and eighth characters have each one 5 possible choices. There are seven characters left. None of them are a vowel, but they are allowed to take any other letter or digit, so each one of them can be chosen in 36-5=31 ways. Therefore there are strings.
- d) Remember that the binomial coefficient
is the number of ways of choosing k elements from a set of n elements. In this case, to count all the possible strings, we first need to count in how many ways we can select the four positions that will have the digits. This can be done in 
ways, since we are choosing four elements from the set of the ten positions of the string. Now, for the first position, we can choose any digit so it has 10 possibilities. The second position has 9 possibilities, because we can't repeat the digit used on the first position. Similarly, there are 8 choices for the third position and there are 7 choices for the fourth. Now, these are the only digits on the string, so the remaining 6 characters must be letters, then each one of them has 26 possibilities. By the product rule, there are strings.
