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egoroff_w [7]
1 year ago
7

One slice of cheese pizza contains 310 calories. A medium-size orange has one-fifth that number of calories. How many calories a

re in a medium-size orange? -Please help me understand!
Mathematics
2 answers:
I am Lyosha [343]1 year ago
7 0
The medium sized orange would have 62 calories. To divide by 1/5, which in decimal form is 0.2, you just multiply 310 by 0.2, therefore, giving you 62. Hope this helps! 
3241004551 [841]1 year ago
6 0
We must divide the number of calories in the pizza by five to find out how many calories are in the medium-size orange.

310 / 5 = 62

There are 62 calories.
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A circle fits inside a semicircle of diameter 24mm
patriot [66]

Answer:

The shaded are is 113\ mm^{2}

Step-by-step explanation:

we know that

The shaded area is equal to the area of the semicircle minus the area of the circle inside the semicircle

step 1

Find the area of semicircle

The area of semicircle is equal to

A=\frac{1}{2}\pi r^{2}

where

r=24/2=12\ mm ----> the radius is half the diameter

substitute

A=\frac{1}{2}\pi(12)^{2}=72\pi\ mm^{2}

step 2

Find the area of the circle inside the semicircle

The area of circle is equal to

A=\pi r^{2}

where

r=12/2=6\ mm ---> the radius of circle inside is half the radius of semicircle

substitute

A=\pi(6)^{2}=36\pi\ mm^{2}

step 3

Find the shaded area

72\pi\ mm^{2}-36\pi\ mm^{2}=36\pi\ mm^{2}

assume

\pi=3.14

36(3.14)=113.04\ mm^{2}

3 significant figures is

113\ mm^{2}

6 0
1 year ago
Which statement identifies how to show that j(x) = 11.6ex and k(x) = In (StartFraction x Over 11.6 EndFraction) are inverse func
Vadim26 [7]

Answer:

<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>

Step-by-step explanation:

Given the function  j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6}, to show that both equality functions are true, all we need to show is that both  j(k(x)) and k(j(x)) equal x,

For j(k(x));

j(k(x)) = j[(ln x/11.6)]

j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}

j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)

j[(ln x/11.6)] = 11.6 * x/11.6

j[(ln x/11.6)] = x

Hence j[k(x)] = x

Similarly for k[j(x)];

k[j(x)] = k[11.6e^x]

k[11.6e^x] = ln (11.6e^x/11.6)

k[11.6e^x]  = ln(e^x)

exponential function will cancel out the natural logarithm leaving x

k[11.6e^x]  = x

Hence k[j(x)] = x

From the calculations above, it can be seen that j[k(x)] =  k[j(x)]  = x, this shows that the functions j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6} are inverse functions.

4 0
1 year ago
Here is a typical statement made by the media: "Based on a recent study, pennies weigh an average of 2.5 grams with a margin of
Damm [24]
The answer is A I think
8 0
2 years ago
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A bottle of white wine at room temperature (68°f) is placed in a refrigerator at 4 p.m. its temperature after t hr is changing a
Nat2105 [25]
After an hour (4pm to 5pm) the temperature drops 18e⁻⁰˙⁶=9.9℉, so the temperature after an hour will be 68-9.9=58.1℉.
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5 0
2 years ago
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Slope-intercept form is y = mx +b, where the variable m represents the slope of the line and the variable b represents the y-intercept of the line. Since we weren't given the y-intercept, one way to solve this problem is substitute the slope for the variable m and then the x and y values from the ordered pair to solve for b.

y = mx + b

y = 3x + b

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Now, we can simplify by computing the multiplication on the right side of the equation.

-4 = 27 + b

Finally, we can find the value for b by subtracting 27 from both sides of the equation to get:

-31 = b

Now, we should substitute this value for b back into our equation with the slope.

y = 3x - 31

Therefore, your answer is y = 3x - 31.

Hope this helps!

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