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Ivanshal [37]
2 years ago
7

I am an odd number I am less than 100 the sum of my digits is 12 I am a multiple of 15 what number am I

Mathematics
1 answer:
ivolga24 [154]2 years ago
6 0

The answer is 75.


Let's look at your problem shall we:


Odd number: It should end with the numbers 1,3,5,7, and 9.

The number is less than 100: It should be from the number 1-99

Sum of digits: 12

Multiple of 15: 15, 30, 45, 60, 75, and 90.


We can rule out 30, 60, and 90 because they are even.

1+5 = 6; 4+5=9; 7+5 = 12


You are left with 75.

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A rectangular plot of land that contains 1500 square meters will be fenced and divided into two equal portions by an additional
WINSTONCH [101]
Let x = the length of the rectangle
Let w= the width

Two sections are required, hence 2w of fence required
2x+3w=500

this can be written as:
3w=1500-2x
w=(1500-2x)/3

Area=x*w
replacing w with our expression:
A=x(1500-2x)/3
A=(500x-2x^2)/3

This is a quadratic equation, if we find the axis of symmetry we will know what value of x gives maximum area:
Axis of symmetry: x=-b/2a
From our equation we get:
a=-2/3; b=1500/3
thus
x=(1500/3)/(-(-2/3))
x=750
thus the maximum area will be given by length of 750
3 0
2 years ago
Connor has seven more nickels than dimes and twice as many quarters as dimes. If he has $6.20, how many nickels does he have?
Novosadov [1.4K]
Connor has 16 nickels. If you have 9 dimes (90 cents) and you doubled it that would give you 18 quarters ($4.50). you have 7 more nickels than dimes, so you do 7+9 which equals 16 nickels (80 cents). 90+450+80=620.
8 0
2 years ago
Imagine working in a freelance developer earning 80 USD per hour how many weeks you will have to take a 12 hour flight on a week
Sever21 [200]

Answer:

pay the 11 AM ticket

Step-by-step explanation:

Note that the flight last for 12 hours, and assuming the freelance developer can still work (have access to the internet) on the airplane throughout the flight, he stand to earn $960 ($80*12), which will still cover the cost of the flight with a profit of $60 ($960-900).

However, if he decides to pay the $11 flight ticket and there is no Internet on boards; there by losing a day of work, he stand to have lost working time which would earn with $900.

Therefore, the best choice is to pay the 11 AM ticket.

3 0
2 years ago
Solve the following quadratic equations by extracting square roots.Answer the questions that follow.
Vikentia [17]

Answer:

1.  x=±4

2. t=±9

3. r=±10

4. x=±12

5. s=±5

Step-by-step explanation:

1. x^2 = 16

Taking square root on both sides

\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\

x=±4

2. t^2=81

Taking square root on both sides

\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}

t=±9

3. r^2-100=0

r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}

r=±10

4. x²-144=0

x²=144

Taking square root on both sides

\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}

x=±12

5. 2s²=50

\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}

s=±5 ..

4 0
2 years ago
Read 2 more answers
Suppose that on a certain examination in advanced mathematics, students from univer sity A achieve scores that are normally dist
harkovskaia [24]

Answer:

P(z>-1.768)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the scores for the univerisity A, and we know that:

X \sim N (\mu = 625,\sigma =\sqrt{100}= 10)

Let Y the scores for the univerisity B, and we know that:

Y \sim N (\mu = 600,\sigma =\sqrt{150}= 12.25)

We select a sample size of size n=2, and since the distirbution for X is normal then the distribution for the sample mean would be given by:

\bar X \sim N(\mu=625, \frac{\sigma}{\sqrt{n}}=\frac{10}{\sqrt{2}}=7.07)

And for the univeristy B we select a sample of n=3

\bar Y \sim N(\mu=600, \frac{\sigma}{\sqrt{n}}=\frac{12.25}{\sqrt{3}}=7.07)

Since both sample means are normally distributed then the difference Z= \bar X- \bar Y is also normal distributed with the following parameters:

Z= \bar X -\bar Y \sim N(\mu_Z=625-600=25, \sigma_z= \sqrt{100+100}=14.14)

And we want this probability:

P(Z>0)

And we can use the z score given by:

Z= \frac{z -\mu_z}{\sigma_z}

And if we replace we got :

Z= \frac{0-25}{14.14}=-1.768

And if we find the probability using the normla standard table or excel we got:

P(z>1.768) =1-P(Z

3 0
2 years ago
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