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vredina [299]
1 year ago
9

Nswer two questions about Systems A AA and B BB: System A AA start text, end text System B BB { − 3 x + 12 y = 15 7 x − 10 y = −

2 ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ −3x+12y=15 7x−10y=−2 ​ { − x + 4 y = 5 7 x − 10 y = − 2 ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ −x+4y=5 7x−10y=−2 ​ 1) How can we get System B BB from System A AA? Choose 1 answer: Choose 1 answer: (Choice A) A Replace one equation with the sum/difference of both equations (Choice B) B Replace only the left-hand side of one equation with the sum/difference of the left-hand sides of both equations (Choice C) C Replace one equation with a multiple of itself (Choice D) D Replace one equation with a multiple of the other equation
Mathematics
1 answer:
rjkz [21]1 year ago
7 0

Answer:

(Choice C) C Replace one equation with a multiple of itself

Step-by-step explanation:

Since system A has the equations

-3x + 12y = 15 and 7x - 10y = -2 and,

system B has the equations

-x + 4y = 5 and 7x - 10 y = -2.

To get system B from system A, we notice that equation -x + 4y = 5 is a multiple of -3x + 12y = 15 ⇒ 3(-x + 4y = 5) = (-3x + 12y = 15).

So, (-x + 4y = 5) = (1/3) × (-3x + 12y = 15)

So, we replace the first equation in system B by 1/3 the first equation in system A to obtain the first equation in system B.

So, choice C is the answer.

We replace one equation with a multiple of itself.

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A 3^{\text{rd}}3 rd 3, start superscript, start text, r, d, end text, end superscript degree binomial with a constant term of 88
LiRa [457]

Answer:

See explanation

Step-by-step explanation:

A 3rd degree binomial with a constant term of 8

A binomial expression is an expression which has only terms such as: x² + 5

The degree of a polynomial is the term with the highest exponent on its variable.

Example: the expression above x² + 5

The exponent of variable, x is 2

So, it is a 2nd degree polynomial

We also have 1st degree polynomial where the highest exponent on the variable is 1

3rd degree polynomial where the highest exponent on the variable is 3

A 3rd degree binomial with a constant term of 8

1. There must be a variable, let say x

2. The highest exponent on the variable must be 3

3. There must be a constant 8

4. The expression must have two terms only

It could be x² + 8 where the coefficient of x is 1

2x² + 8

3x² + 8

It could take any form as long as the highest exponent on the variable is 3 and there are just two terms

7 0
1 year ago
A newly introduced fitness program is gaining popularity among the members of a fitness club. The number of members, s(1), who j
ahrayia [7]

Answer:

Option A will be the answer.

Step-by-step explanation:

The number of members, s(t), who joined the  program t months after it was introduced is modeled by the function below  

s(t) = 10(2)^{x}  + 10

The function is an exponential function and y-intercept of the function is at (0,20) point.

Now, from the graph given in the options, the first graph matches the criteria.

Hence, option A will be the answer. (Answer)

6 0
2 years ago
An experiment is carried out 400 times.
MissTica

Answer:

You would expect the outcome to be void 240 times

Step-by-step explanation:

1000 x 0.24

6 0
2 years ago
Select all the pairs that could be reasonable approximations for the diameter and circumference of a cirlce 5 meters and 22 mete
bazaltina [42]

Answer:

Option a) circle 5 meters and 22 meters

Step-by-step explanation:

We are given the following information in the question:

A pair of diameter and the circumference is given. We have to find a correct approximations for the diameter and circumference.

a) circle 5 meters and 22 meters

\text{Diameter} = 5\text{ meters}\\\text{Circumference} = \pi d = 3.14\times 5 = 15.7\text{ meters}

b) 19 inches and 50 inches

\text{Diameter} = 19\text{ inches}\\\text{Circumference} = \pi d = 3.14\times 19 = 59.66\text{ inches}

c) 33 centimeters and 80 centimeters

\text{Diameter} = 33\text{ centimeters}\\\text{Circumference} = \pi d = 3.14\times 33 =103.62\text{ centimeters}

Thus, no pair gives a reasonable approximation. Only the circle with diameter 5 and circumference 22 meters have closest approximation.

6 0
2 years ago
Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord
andrew-mc [135]
Consider the circle with center X, as shown in the figure. 

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is  

\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8 units.


Answer: 8 units

7 0
2 years ago
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