If 400 mL of a 20% w/v solution were diluted to 2 L, what would be the final percentage strength?
1 answer:
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Answer:
For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:
b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.
Step-by-step explanation:
Notation
represent the sample mean for the sample
population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
(1)
In order to calculate the mean and the sample deviation we can use the following formulas:
(2)
(3)
In order to calculate the critical value we need to find first the degrees of freedom, given by:
For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:
b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.