All categories

2 years ago

Explain how you know the values of the digits in the number 58

Mathematics

1 answer:

AleksAgata [21]2 years ago

6 0

The value of 5 is 50 because its in the tens place the value of 8 is 8 because its in the ones place.

You might be interested in

A country is considering two income tax rates. Geoffrey is comparing what his tax bill would be under each plan. Under plan A, h

worty [1.4K]

98000*0.15 is how you would find out how much he has to pay for tax, which is 14700. since you didn't post plan b, this is all i can do.

5 0

2 years ago

Read 2 more answers

LeAnn wants to giftwrap a present she got for her little brother. How many square inches of giftwrap will be needed to cover a b

Sloan [31]

For this case we must find the surface area of a rectangular prism.
We have then:
$A = 2 * (w * l) + 2 * (w * h) + 2 * (l * h)
$
Where,
w: width
l: long
h: height
Substituting values we have:
$A = 2 * (4 * 6) + 2 * (4 * 2) + 2 * (6 * 2)

A = 88 in ^ 2$
Answer:
There will be needed 88 in ^ 2 of giftwrap to cover the box

8 0

2 years ago

Eli needs pieces of ribbon cut into strips that are 2 1\2 feet long. The roll of ribbon is 7 1\2 feet long. Which expression cou

julsineya [31]

Answer: There are 3 strips that can be cut from the roll of ribbon.

Step-by-step explanation:

since we have given that

Length of a ribbon is given by

$7\frac{1}{2}\ ft\\\\=\frac{15}{2}\ ft$

Length of pieces of ribbon cut into strips is given by

$2\frac{1}{2}\ ft\\\\=\frac{5}{2}\ ft$

So, we need to find the number of strips that can be cut is given by

$\text{ Number of strips }=\frac{\text{Length of roll}}{\text{ Length of strip}}\\\\=\frac{\frac{15}{2}}{\frac{5}{2}}\\\\=\frac{15\times 2}{2\times 5}\\\\=\frac{15}{5}\\\\=3$

Hence, there are 3 strips that can be cut from the roll of ribbon.

6 0

2 years ago

Read 2 more answers

In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram? AB ≅

siniylev [52]

For any quadrilateral to be a parallelogram

i) either both the pairs of opposite sides must be equal

ii) Both the pairs of opposite sides must be parallel

iii) Opposite pairs of angles must be equal

iv) Diagonals must bisect each other.

v) A pair of opposite sides must be parallel and equal

Here we are already given that AB || CD

So either we should be given that AD || BC

or we must be given that AB = CD

Here it is given AB = CD as an option.

So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.

7 0

2 years ago

Read 2 more answers

PLEASE HELP ASAP: A particle is moving with velocity v(t) = t2 – 9t + 18 with distance, s measured in meters, left or right of z

dimaraw [331]

1) $\frac{v(8)-v(0)}{8 - 0} = \frac{10-18}{8} = -1\frac{m}{s}$ .
2) $v(5) = 5^2-9*5+18 = 25-45+18 = -2\frac{m}{s}$ .
3) The particle is moving right when the velocity function is positive: $0\ \textless \ t\ \textless \ 3$ or $6\ \textless \ t\ \textless \ 8$ .
4) When $0\ \textless \ t\ \textless \ \frac{9}{2}$ the particle is slowing down because the acceleration is close to zero $\Rightarrow$ the particle is speeding up when acceleration is increasing away from zero: $\frac{9}{2}\ \textless \ t\ \textless \ 8$ .
5) $(\frac{1}{8})* \int\limits^8_0 {t^2-9t+18dt}=\frac{1}{8}*(\frac{t^3}{3}-(\frac{9}{2}*t^2+18t)_{0}^{8}= \\=(\frac{1}{8})*(\frac{8^3}{3}-(\frac{9}{2})*8^2+18*8)=\frac{8^2}{3}-(\frac{9}{2})*8+18=3\frac{1}{3} \frac{m}{s}$ .

3 0

2 years ago