So what I did was as $32.50 twice and got $65.00 and subtracted it with $212.50 and got $152.50. Hope i was helpful!
Answer:
the probability that the project will be completed in 95 days or less, P(x ≤ 95) = 0.023
Step-by-step explanation:
This is a normal probability distribution question.
We'll need to standardize the 95 days to solve this.
The standardized score is the value minus the mean then divided by the standard deviation.
z = (x - xbar)/σ
x = 95 days
xbar = mean = 105 days
σ = standard deviation = √(variance) = √25 = 5
z = (95 - 105)/5 = - 2
To determine the probability that the project will be completed in 95 days or less, P(x ≤ 95) = P(z ≤ (-2))
We'll use data from the normal probability table for these probabilities
P(x ≤ 95) = P(z ≤ (-2)) = 0.02275 = 0.023
Katie is 6; Cathy is 18!
X- Katie’s age now and 3x -Cathys age now
In 6 years, Katie is 12 and Cathy is 24.
2 x (X+6) = 3x + 6
2x + 12 = 3x + 6
6 = x
we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
