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1 year ago

If π is rounded to a whole number, what is a reasonable estimate for the circumference of a circle with a diameter of 9 cm?

1 answer:

8 0

Pi rounded to a whole number would equal three. Circumference equals 2pi*r. The radius in this case is half of the diameter, so 4.5 cm. 2 times pi, or three equals 6 times 4.5 is 27

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Bernie helped design a magician costume for a school play. He used 5.75 feet of ribbon for the magician's wand. He used 11.75 fe

Nonamiya [84]

Answer:

The ribbon cost per foot $0.6 per foot

Step-by-step explanation:

Total number of ribbon used = (5.75 + 11.75) = 17.50 feet

17.50 feet of ribbon cost = $10.50

1 foot of ribbon cost = x

Cross Multiply

17.50 × x = 1 foot × $10.50

x = 1 foot × 10.50/17.50

x = $0.6

The ribbon cost per foot $0.6 per foot

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1 year ago

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PLEASE HELP MATH EXPAND LOG

blsea [12.9K]

Answer:

½log3 + ½logx

Step-by-step explanation:

½(log(3x))

½(log3 + logx)

½logx + ½log3

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1 year ago

Suppose a snow cone has a paper cone that is 8 centimeters deep and has a diameter of 5 centimeters. The flavored ice comes in a

Neko [114]

check the picture below.

so the cone itself has a height of 8, and a radius of 2.5, and the spherical scoop, ready to melt in it, has a radius of 2.5.

namely, will the volume of the sphere be larger than the cone? in which case the melted ice-cream will overflow.

$\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=2.5\\ h=8 \end{cases}\implies V=\cfrac{\pi (2.5)^2(8)}{3}\implies \implies \boxed{V=\cfrac{50\pi }{3}} \\\\\\ \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad r=2.5\implies V=\cfrac{4(\pi )(2.5)^3}{3}\implies \boxed{V=\cfrac{125\pi }{6}} \\\\\\ \textit{the sphere's volume is larger, so yes, it will overflow}$

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1 year ago

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Kelly hiked in the woods it took her 1/14 hour to walk 1/4 mile after she snacked she walked another 1/6 mile in 1/16 hour

mariarad [96]

General Idea:

The relationship between rate(R), distance(D) and time(T) given below:

$R= \frac{D}{T}$

Applying the concept:

We need to make use of the formula to find Kelly's walking rate before and after her snack

$Kelly \; Walking \; Rate \; before \; Snack:\\Distance \div Time = \frac{1}{4} \div \frac{1}{14} = \frac{1}{4} \times \frac{14}{1} = \frac{14}{4} = \frac{7}{2} = 3 \frac{1}{2} \; miles \; per \; hour\\\\Kelly \; Walking \; Rate \; after \; Snack:\\Distance \div Time = \frac{1}{6} \div \frac{1}{16} = \frac{1}{6} \times \frac{16}{1} = \frac{16}{6} = \frac{8}{3} = 2 \frac{2}{3} \; miles \; per \; hour\\\\$

Option A isn't correct because before snack Kelly walking rate is not 4/14 miles per hour.

Option B is <u>Correct,</u> Kelly walking rate after snack is 2 2/3 miles per hour.

Option C isn't correct because it doesn't took Kelly 2 hours longer to walk 1/6 mile than it did for her to walk 1/4 mile. It took 1/112 hour longer.

$\frac{1}{14} - \frac{1}{16} = \frac{1 \cdot 8}{14 \cdot 8} - \frac{1 \cdot 7}{16 \cdot 7} = \frac{8}{112} - \frac{7}{112} = \frac{1}{112}$

Option D isn't correct because 2 2/3 miles per hour is slower than 3 1/2 miles per hour.

Conclusion:

Option B is <u>Correct,</u> Kelly walking rate after snack is 2 2/3 miles per hour.

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1 year ago

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Jeff saved $500 from his summer job so he would have spending money during the school year. He withdraws $12 from his account ea

Alex Ar [27]

Jeff Lucy Goethe licky

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1 year ago