All categories

2 years ago

To solve 16x18, I double and halve?

1 answer:

8 0

To solve 16x18, you may split it up into a smaller increment you understand. Like 16x2, which equals 32. (18/2 is 9) multiply 32 by 9. you get your answer 288.

You might be interested in

11.

olga_2 [115]

Your answer is B!!!! :D

6 0

2 years ago

A car wash charges two prices depending on the size of the vehicle. The table shows the number of cars and the number of SUVs wa

Scrat [10]

Answer:

see below

Step-by-step explanation:

In the system of equations, x represents the, price to wash a car and y represents the price to wash an SUV.

If the system of equations is graphed in a coordinate plane, the coordinates (x, y) of the intersection of the two lines are the price of the car wash (x) and the price of the SUV wash (y)______.

x=12 and y = 18

x+y = 12+18 = 30

The total cost of 1 car and 1 SUV is $_30____.

5x+4y = 5(12)+4(18) = 60+ 72 =132

The total earnings for hour 3 are $_132_____.

3 0

2 years ago

Read 2 more answers

Amy is biking to school from her father's house and Jeremy is biking to school from his aunt's house. Suppose Amy is moving at a

Mnenie [13.5K]

No, having the greater rate of change does not mean a function will necessarily reach an output with the smallest input. It also depends on the initial values of the functions. If Jeremy's aunt lives closer to school, Jeremy's rate of change is smaller, but he could still get to school before Amy.

9 0

2 years ago

Read 2 more answers

Mr. Rodriguez, a college instructor, can grade his class papers in 3 hours while it takes his assistant 4 1/2 hours. If Mr. Rodr

cricket20 [7]

3 1/2 hours because Rodriquez graded one hour of papers and if his assistant grades the class papers in 4 1/2 hours, it should only take him 3 1/2 hours since Rodriquez helped with an hour of it

7 0

2 years ago

Simplify sin θ / square root 1 - sin^2 θ

Soloha48 [4]

Recall that

$\cos^2\theta+\sin^2\theta=1$

which means

$\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{\sqrt{\cos^2\theta}}$

Now, $\cos\theta$ could be positive or negative, which means $\sqrt{\cos^2\theta}=|\cos\theta|$ . If we specifically knew the sign of $\cos\theta$ was positive, then we can simplify and write

$\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{\cos\theta}=\tan\theta$

or if it's negative,

$\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{-\cos\theta}=-\tan\theta$

7 0

2 years ago