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MArishka [77]
2 years ago
14

According to a Pew Research Center report from 2012, the average commute time to work in California is 27.5 minutes. To investig

ate whether a different average is true for the small city that she lives in, a California high school student surveys 45 people she knows-her teachers, her parents and their friends and co-workers - and finds the average commute time for this sample to be 24.33 minutes, with a standard deviation of 9.53 minutes The data were not strongly skewed
a. Identify the observational units for this study.

b. Identify the variable of interest and state whether it is categorical or quantitative.

c. Identify (in words and using an appropriate symbol) the parameter of interest
Mathematics
1 answer:
FinnZ [79.3K]2 years ago
7 0

Answer:

b. Identify the variable of interest and state whether it is categorical or quantitative.

Step-by-step explanation:

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Sid has £5 to buy apples and bananas.
Simora [160]
He buys 18 apples = £1.08
He can buy 9 bananas
8 0
2 years ago
Read 2 more answers
A County Superintendent of Highways is interested in the numbers of different types of vehicles that regularly travel within his
Karolina [17]

Answer:

a) The ratio of passenger cars to pickup trucks is \frac{5}{7}

The ratio of pickup trucks to passenger cars is \frac{7}{5}

The ratio of passenger cars to total vehicles is \frac{5}{12}

The ratio of pickup trucks to total vehicles is \frac{7}{12}

b) The tape diagram is shown in the attached picture.

c) The tape diagram has 12 equal-sized parts.

d) The total quantity that the tape diagram represent is 192.

e) The value of each individual part of the tape is 16.

f) There were registered 80 passenger cars and 112 pickup trucks.

Step-by-step explanation:

a) According to the information in the problem, that for every 5 passenger cars registered, there were 7 pickup trucks registered.

So the ratios are:

Passenger cars to pickup trucks: \frac{5}{7}

Pickup trucks to passenger cars: \frac{7}{5}

If we calculate the total vehicles: 5+7=12

So, we can get two ratios more:

Passenger cars to total vehicles is \frac{5}{12}

Pickup trucks to total vehicles is \frac{7}{12}

b) We make a tape diagram where each box represents a vehicle so we draw 5 boxes for cars and 7 boxes for pickup trucks.

c) If we count the total quantity of boxes, there are 12.

d) This diagram represents the total quantity of registrations in August which is 192.

e) To get the representation of each part of the tape diagram we have to divide 192 by 12. 192÷12=16

f) Finally, we multiply 16 by the number of boxes of each type of vehicle:

Cars: 16×5=80

Pickup trucks: 16×7=112

6 0
2 years ago
The Venn diagram shows the results of two events resulting from rolling a number cube.
tankabanditka [31]

Answer:

P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{1}{3}

P(A) =\frac{2}{3}

P(B) =\frac{1}{2}.

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

P(A) = \frac{4}{6} = \frac{2}{3}

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

P(B) = \frac{3}{6} = \frac{1}{2}.

Now

P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}

6 0
2 years ago
The heights of students at a college are normally distributed with a mean of 175 cm and a standard deviation of 6 cm. One might
frosja888 [35]

Answer:

25

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 175cm

Standard deviation = 6 cm

Percentage of students below 163 cm

163 = 175 - 2*6

So 163 is two standard deviations below the mean.

By the Empirical rule, 95% of the heights are within 2 standard deviations of the mean. The other 100-95 = 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of them are more than 2 standard deviations below the mean(so below 163cm) and 2.5% are more than two standard deviations above the mean.

2.5% of the students have heights less than 163cm.

Out of 1000

0.025*1000 = 25

25 is the answer

8 0
2 years ago
Read 2 more answers
Katy had two choices of routes to get her to work. She wanted to choose the route that would get her to work fastest, on average
zmey [24]

Answer:

D. There is not enough evidence at the 5% significance level to indicate that one route gets Katy to work faster, on average, since 0 falls within the bounds of the confidence interval.

Step-by-step explanation:

At 5% confidence level, Katy found difference in mean commuting times (Route 1-Route 2) in minutes as (-1,9).

Since no difference in means (0 min) falls within the confidence level (-1,9), we can not reject the hypothesis that there is no difference in mean commuting times when using Route1 or Route2.

A <em>higher</em> significance level(10% etc) may lead a <em>shorter</em> confidence interval leaving 0 outside and may reach a conclusion that Route1 takes longer than Route2

4 0
2 years ago
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