Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
H0: µ = 5000
For the alternative hypothesis,
H1: µ > 5000
Since the population standard deviation is given, z score would be determined from the normal distribution table. The formula is
z = (x - µ)/(σ/√n)
Where
x = sample mean
µ = population mean
σ = population standard deviation
n = number of samples
From the information given,
µ = 5000
x = 5430
σ = 600
n = 40
z = (5430 - 5000)/(600/√40) = 4.53
Looking at the normal distribution table, the probability corresponding to the z score is < 0.0001
Since alpha, 0.05 > than the p value, then we would reject the null hypothesis. Therefore, at a 5% level of significance, it can be concluded that they walked more than the mean number of 5000 steps per day.
Hey there!
Before you start solving anything, you need to identify which situation you want to call event A and which you want to call event B. I usually just do it in the order of the events as they're given to me in the question, so:
A = S<span>tudent participates in student council
B = S</span><span>tudent participates in after school sports
Any problems that contain the word "given" in the question portion will want you to refer to </span>P(A | B)<span> = P(</span>A ∩ B)/P(B). P(A | B) literally means "probability of event A, given that event B has occurred." P(A ∩ B) is the probability of event A and B happening, and P(B) is just the probability of event B happening. We've been given all of that, so:
P(A | B) = P(A ∩ B)/P(B)
P(A | B) = 11% / 62%
P(A | B) = 0.11 / 0.62
P(A | B) = 0.18
There will be about an 18% chance that <span>a student participates in student council, given that the student participates in after school sports.
Hope this helped you out! :-)</span>
Answer: 957.8
Step-by-step explanation:
To answer this question, you need to makes the unit of the smartphone screen same. In this case, phone A is using decimal and phone B is using a fraction. You can use which was easier.
Let's try to use decimal. Then you need to convert phone B fraction width into decimal width. The calculation would be: 5cm + 1/3cm= 5 cm + 0.333cm= 5.333cm
From here it clear that phone B has a wider screen than phone A.
