Question

The average MCAT score follows a Normal distribution, with a mean of μ = 508 and a standard deviation of σ = 8. What is the probability that the mean IQ score of 100 randomly selected people will be more than 510?
0.0062
0.9938
0
0.4013
0.5987

Answer 1

Subtract the mean from the high score and divide by the standard deviation:

510 - 508 = 2

2/8 = 0.25

Using the Z tabe find the z value for 0.25 = 0.5987

Now subtract that value from 1:

1 - 0.5987 = 0.4013

Answer 2

Answer:

0.4013

Step-by-step explanation:

(Just want to note I am not the best at explanations but here is what I came up with to save you some time)

I watched a vid with sample questions so i realized I needed to get my graphing calculator and input my info into normal cdf

Inputing

(510,999,508,8) = 0.40129....... = .4013

Hope this helped :)