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2 years ago

A= 49 sq. in. Find the value of x. If necessary, round to the nearest tenth.

Mathematics

2 answers:

BlackZzzverrR [31]2 years ago

8 0

Answer:

9.90 inches

Step-by-step explanation:

Area of a triangle is equal to base times height divided by 2.

$bh/2$

Base and height is x.

$xx/2=49$

Solve for x.

$x^2=49 \times 2$

$x^2=98$

$x=\sqrt{98}$

$x=9.899495$

solniwko [45]2 years ago

8 0

A=1/2bh :area of a triangle
because the base and height are both x you must multiply x•x = x square

49= 1/2x^2
98= x^2
x= 9.9

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