∑ from 1 to infinity of 12(3/5)^(i - 1)
Since the common ratio is less than 1, the series is convegent. [i.e. 3/5 < 1]
Sum to infinity of a geometric series is given by a/(1 - r); where a is the first term, and r is the common ratio.
Sum = 12/(1 - 3/5) = 12/(2/5) = 30.
Answer:
17
Step-by-step explanation:
$15+$27=$42
$712 divided by $42 is 17 meaning there are 17 kids in the class.
To find the answer you would add 27 and 8 together which would give you 35. Once you've done that, you would subtract 32 from 35 which would give you 3 meaning that there will be 3 pallets left over as your answer.
The answer is -16 - 10i.
Using the distributive property on the first part, we have:
-2i*7--2i*4i + (3+i)(-2+2i)
-14i+8i² +(3+i)(-2+2i)
Using FOIL on the last part,
-14i+8i²+(3*-2+3*2i+i*-2+i*2i)
-14i+8i²-6+6i-2i+2i²
-10i+8i²-6+2i²
Since we know that i = -1,
-10i+8(-1)-6+2(-1)
-10i-8-6-2
-16-10i
