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erik [133]
2 years ago
10

In a shipment of 850 widgets, 32 are found to be defective. At this rate, how many defective widgets could be expected in 22,000

widgets? Round to the nearest whole number.
Mathematics
1 answer:
Kobotan [32]2 years ago
3 0
You can solve this using fractions, and say that 32/850 are defective. To find the amount of defective widgets out of 22,000, we can then multiply to make the denominator 22,000. To work out what we need to multiply by, we can just do 22,000 ÷ 850 = 25.88. Now if we multiply 32 by 25.88, we get our answer as 828 widgets.

I hope this helps!
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2 years ago
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Answer:

The fourth term of the expansion is -220 * x^9 * y^3

Step-by-step explanation:

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Find the fourth term in (x-y)^12

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3 0
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