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nydimaria [60]
2 years ago
12

∠ABC and ∠DBC are complementary angles. If m∠ABC=6x+13 and m∠DBC=4x−3 what is the value of x?

Mathematics
1 answer:
egoroff_w [7]2 years ago
4 0

Answer:

x=8

Step-by-step explanation:

Complementary angles are equal to 90 degrees.

angle ABC + angle DBC = 90

6x+13+4x-3=90

Combine like terms

6x+4x+13-3=90

10x+10=90

get x alone by subtracting 10 on both sides

10x=80

divide 10 on both sides

x=8

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Mg+rg=2H, solve for g
Simora [160]

Answer:

g=\frac{2\,H}{m+r}

Step-by-step explanation:

Starting with :

m g + r g = 2 H

extract "g" as a common factor on the left of the equal sign:

g (m + r) = 2 H

Now, in order to solve for "g" , divide both sides of the equal sign by the binomial (m + r):

g = (2 H )/(m + r)

g=\frac{2\,H}{m+r}

4 0
2 years ago
Which is bigger 0.96 0r 19/20
REY [17]
0.96 or 19/20

0.96 as fraction = 96/100 = 19.2 / 20      5 into 96 is 19.2 and 5 into 100 is 20

So 0.96 is the same as 19.2/20

Since 19.2 / 20  and 19 / 20 have the same denominator,  therefore the 19.2 / 20 is bigger than 19 / 20.

So the 0.96 is bigger than the 19 / 20.
7 0
2 years ago
explain the relationship between multiplying and dividing by 10 100 1000 and moving decimals point to the right or to the left
ch4aika [34]

So basically a decimal is moved based on how many zeros are in the dividing number

Ex. 51,000/100

because there are 2 zeros in the number one hundred, the decimal in 51,000 gets moved 2 places to the left

So it goes from 51,000 to 510

Ex. 16 * 1000

There are three zeros in the number 1000. This means three zeros will be added onto the number 16

So the answer would be 16,000

Hope this helps!

6 0
2 years ago
An airplane is flying at a speed of 500 mi/h at an altitude of one mile. The plane passes directly above a radar station at time
d1i1m1o1n [39]

Answer:

a)s=\sqrt{1+d^2}

b)d(t)=500t

c)s(t) =\sqrt{1+250000t^2}

Step-by-step explanation:

d = Horizontal distance

s = the distance between the plane and the radar station

The horizontal distance (d), the one mile altitude, and s form a right triangle.

So, use Pythagoras theorem

Hypotenuse^2=Perpendicular^2+Base^2

s^2=1^2+d^2

a) s=\sqrt{1+d^2}

(b) Express d as a function of the time t (in hours) that the plane has flown.

distance = speed \times time

d(t)=500t

(c) Use composition to express s as a function of t.

s(t) =\sqrt{1+d^2}

using b

s(t) =\sqrt{1+(500t)^2}\\s(t) =\sqrt{1+250000t^2}

6 0
2 years ago
Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0? u2 – 11u + 24 = 0 where u = (x2 – 1) (u2)2 – 11(u2) +
Vinvika [58]
<span><span>u2</span> – 11u + 24 = 0 where u = (x2 – 1) the first awnser, a.</span>
4 0
2 years ago
Read 2 more answers
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