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1 year ago

M∠AFD=90°. m∠AFB=31°. Find m∠CFEm.

Mathematics

2 answers:

Setler [38]1 year ago

7 0

AFB = CFD = 31
BFC = 90 - (31+31) = 28
DFE = BFC = 28
CFE = CFD + DFE = 31 + 28 = 59

olya-2409 [2.1K]1 year ago

3 0

Answer with explanation:

→ m∠AFD=90°

→ m∠AFB=31°=m∠CFD--------[Given]----(1)

→m ∠BFC=m ∠DFE-------[Given]

⇒m∠AFB + m ∠BFC +m ∠CFD=90°--------[Given]

⇒31°+ m ∠BFC +31°=90°-------[Using 1]

⇒m ∠BFC =90° -62°

⇒m ∠BFC = 28°

⇒m ∠BFC = 28°=m ∠D FE

⇒m ∠C FE=m ∠D F C+m ∠D FE

= 31° +28°

=59°

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