<h2>
∴Will ran 13.55 yards more than James.</h2>
Step-by-step explanation:
Given Will ran the diagonal distance across a square field measuring 40 yards each sides .
∴The distance covered by Will was =
yards
=
yards=56.56 yards
Again James ran diagonal distance across a rectangle field with a length of 25 yards and a width of 35 yards.
So,distance covered by James was =
yards
=
yards = 43.01 yards
∴Will ran longer distance.
∴Will ran 13.55 yards more than James.
Answer:We can see that this is dependent probability. We can find dependent probability of happening event A then event B by multiplying probability of event A by probability of event B given that event A already happened.
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Step-by-step explanation:In our case event A is pirate hitting captain's ship and event B is captain missing pirate's ship.
We have been given that pirate shoots first so pirate's ship can't be hit before pirate shoots his cannons. So probability of hitting captain's ship is 1/3.
We have been given that if Captain Ben's ship is already hit then Captain Ben will always miss. So the probability of Captain missing the dread pirate's ship given the pirate Luis hitting the Captain ship is 1.
Now to find probability that pirate hits Captain, but Captain misses we will multiply our both probabilities.
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First thing to do is to remember, that the circumference of the full circle is 2(6)pi--12pi. you only want about 120 of it so (120/360)=1/3, so you add it into the thing earlier to get, 12pi(1/3)=4pi =12.566... which you can round into 12.6. This is answer choice A.
Answer:
The critical t values are -1.746 and 1.746.
Step-by-step explanation:
Given information:
The weight of a USB flash drive is 30 grams and is normally distributed.
Population mean = 30
Sample size = 17
Sample mean= 31.9
Standard deviation = 1.8
Significance level, α=0.10
Null hypothesis: 
Alternative hypothesis: 
It is a two tailed test.
The t-critical values for a two-tailed test, for a significance level of α=0.1 are -1.746 and 1.746.
Therefore the critical t values are -1.746 and 1.746.
Answer:
la distancia del punto de observación A al incendio = 5.5 millas
la distancia del punto de observación B al incendio = 3.8 millas
Step-by-step explanation:
La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :
Del siguiente diagrama;
Usando la sine regla:


a sin 79 = 6 sin 63


a = 5.446 millas
la distancia del punto de observación A al incendio = 5.5 millas (a la décima más cercana)


b sin 79 = 6 sin 38


b = 3.7635 millas
la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)