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Vanyuwa [196]
2 years ago
10

A school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel

in the bus. How many ways can the students be seated if all of the second-grade students occupy the first row? A. 25P20 B. 5P5 × 20P15 C. 5C5 × 25C14 D. 5P5 × 15P15 E. 5P5 × 25C15
Mathematics
1 answer:
Nonamiya [84]2 years ago
4 0

Answer:

Option B. 5P5 × 20P15

Step-by-step explanation:

It is very important to remember that the second grade students are sitting in the front row, therefore, it is only necessary to organize 15 first grade students in 20 seats.

Permutations allow you to calculate the number of ways in which m objects can be arranged in n positions.

The permutation of m in n is written as:

nPm

Where n is the number of elements and m are chosen.

The way in which the 5 second grade students can be organized in the 5 seats is from the first row is:

5P5

Then, the number of ways in which 15 first-year students can be organized into 20 seats is:

20P15

Then, the number of ways to organize all students on the bus is the product of both permutations

5P5 * 20P15

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<h2>∴Will ran 13.55 yards more than James.</h2>

Step-by-step explanation:

Given Will ran the diagonal distance across a square field measuring 40 yards each sides .

∴The distance covered by Will was =\sqrt{40^{2}+40^2 } yards

                                                         = 40\sqrt{2} yards=56.56 yards

Again James ran diagonal distance across a rectangle field with a length of 25 yards and a width of 35 yards.

So,distance covered by James was =\sqrt{25^2+35^2} yards

                                                             =5\sqrt{74} yards = 43.01 yards

∴Will ran longer distance.

∴Will ran 13.55 yards more than James.

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2 years ago
Captain Ben has a ship, the H.M.S Crimson Lynx. The ship is five furlongs from the dread pirate Luis and his merciless band of t
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Step-by-step explanation:In our case event A is pirate hitting captain's ship and event B is captain missing pirate's ship.

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While crossing the Atlantic, sailors spot two mermaids 120° apart on each end of an island that is 6 miles away. How far apart a
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2 years ago
The weight of a USB flash drive is 30 grams and is normally distributed. Periodically, quality control inspectors at Dallas Flas
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Answer:

The critical t values are -1.746 and 1.746.

Step-by-step explanation:

Given information:

The weight of a USB flash drive is 30 grams and is normally distributed.

Population mean = 30

Sample size = 17

Sample mean= 31.9

Standard deviation = 1.8

Significance level, α=0.10

Null hypothesis: H_0:\mu=30

Alternative hypothesis: H_1:\mu\neq 30

It is a two tailed test.

The t-critical values for a two-tailed test, for a significance level of α=0.1 are  -1.746 and 1.746.

Therefore the critical t values are -1.746 and 1.746.

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2 years ago
Un guardia forestal divisa, desde un punto de observación A, un incendio en la dirección N27° 10’ E. Otro guardia, que se encuen
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Answer:

la distancia del punto de observación A al incendio = 5.5 millas

la distancia del punto de observación B al incendio = 3.8 millas

Step-by-step explanation:

La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :

Del siguiente diagrama;

Usando la sine regla:

\dfrac{sin \  F}{f} = \dfrac{sin  \ A }{a}

\dfrac{sIn \  79}{6} = \dfrac{sin \   63}{a}

a sin 79 = 6 sin 63

a =\dfrac{6 \times sin \ 63}{sin \ 79}

a =\dfrac{6 \times 0.8910}{0.9816}

a = 5.446 millas

la distancia del punto de observación A al incendio = 5.5 millas (a la décima más cercana)

\dfrac{sin \  F}{f} = \dfrac{sin  \ B}{b}

\dfrac{sin \  79}{6} = \dfrac{sin  \ 38}{b}

b sin 79 = 6 sin 38

b  = \dfrac{6 \times sin  \ 38}{sin \  79}

b  = \dfrac{6 \times0.6157 }{0.9816}

b = 3.7635 millas

la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)

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