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Vanyuwa [196]
2 years ago
10

A school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel

in the bus. How many ways can the students be seated if all of the second-grade students occupy the first row? A. 25P20 B. 5P5 × 20P15 C. 5C5 × 25C14 D. 5P5 × 15P15 E. 5P5 × 25C15
Mathematics
1 answer:
Nonamiya [84]2 years ago
4 0

Answer:

Option B. 5P5 × 20P15

Step-by-step explanation:

It is very important to remember that the second grade students are sitting in the front row, therefore, it is only necessary to organize 15 first grade students in 20 seats.

Permutations allow you to calculate the number of ways in which m objects can be arranged in n positions.

The permutation of m in n is written as:

nPm

Where n is the number of elements and m are chosen.

The way in which the 5 second grade students can be organized in the 5 seats is from the first row is:

5P5

Then, the number of ways in which 15 first-year students can be organized into 20 seats is:

20P15

Then, the number of ways to organize all students on the bus is the product of both permutations

5P5 * 20P15

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You can use a calculator for the decimal operations, but practice some by hand because on the quiz and the test you will not have a calculator.

Step-by-step explanation:

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Jika x1 dan x2 merupakan akar akar persamaan x2+5x-2=0, maka (x1+2x2)(x2+2x1)=
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The distribution of the amount of a customer’s purchase at a convenience store is approximately normal, with mean $15.50 and sta
viktelen [127]

Answer:

0.42 is closest to the proportion of customer purchase amounts between $14.00 and $16.00

Step-by-step explanation:

Mean = \mu = 15.50

Standard deviation = \sigma = 1.72

We are supposed to find the proportion of customer purchase amounts between $14.00 and $16.00

P(14<x<16)

Formula : z=\frac{x-\mu}{\sigma}

At x = 14

z=\frac{14-15.50}{1.72}

z=-0.8720

Refer the  z table for p value

P(x<14)=0.1922

At x = 16

z=\frac{16-15.50}{1.72}

z=0.290

Refer the  z table for p value

P(x<16)=0.6141

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So, Option C is true

Hence 0.42 is closest to the proportion of customer purchase amounts between $14.00 and $16.00

4 0
1 year ago
In ΔVWX, x = 5.3 inches, w = 7.3 inches and ∠W=37°. Find all possible values of ∠X, to the nearest 10th of a degree.
STALIN [3.7K]

Answer:

que?

Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
Ill give a tip
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Divide the APR by 360 days and multiply it by 30 days to get the monthly interest. Each loan is usually secured by the car you bought. So we will use the secured APR.

8. Average rating secured apr: 5.85% divide by 360 multiply by 30:  0.4875% monthly rate
Cost of car: 19,725 ; sales tax: 4.75% ; down payment: 2,175

19,725 x 1.0475 =  20,661.94 - 2,175 = 18,486.94 loan amount
18,486.94 x 0.4875% = 90.12 accrued interest for the 1st month.

9. Excellent rating secured apr: 4.80% divide by 360 multiply by 30: 0.40% monthly rate
Cost of car: 15,867 ; sales tax: 5.25% ; down payment: 10% of total cost

15,867 x 1.0525 =  16,700.02 x 90% = 15,030.02 the principal balance at the start of the loan.

10. Fair rating secured apr: 7% divide by 360 multiply by 30: 0.5833% monthly rate
Cost of new car: 19,072 ; sales tax: 4.5% ; down payment: 1,200
Cost of used car: 15,365; sales tax: 4.5% ; down payment: 1,200

19,072 x 1.045 = 19,930.24 - 1,200 = 18,730.24
18,730.24 x 0.5833% = 109.25 accrued interest

15,365 x 1.045 = 16,056.43 - 1,200 = 14,856.43
14,856.43 x 0.5833% = 86.66 accrued interest

109.25 - 86.66 = 22.59 is the difference in interest accrued by the end of the first month.
7 0
1 year ago
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