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2 years ago

Compare 249 and 271. write the greater number in word form

Mathematics

2 answers:

ipn [44]2 years ago

8 0

Answer:

two hundred seventy-one

Step-by-step explanation:

Given: Two numbers 249 and 271.

To find: Word form of the greater number.

Solution:

We have two numbers 249 and 271.

To find the greater number, we need to compare the two numbers.

To compare the two numbers first of all we will compare the hundreds digit.

The hundreds digit of both the numbers is same that is 2.

Now, we will compare the tens digit of the two numbers.

The tens digit of the number 249 is 4 and the tens digit of the number 271 is 7.

As 7 is greater than 4.

271 is greater than 249.

Now, the word form of 271 is two hundred seventy-one.

boyakko [2]2 years ago

6 0

Two-hundred and forty-nine is less than two hundred and seventy-one

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Two forces, F1 and F2, are represented by vectors with initial points that are at the origin. The first force has a magnitude of

Strike441 [17]

Answer:

Step-by-step explanation:

The two force F1 and F2 are represented by vectors with initial points that are at the origin.

the terminal point of the vector is point P(1, 1, 0)

Therefore, the direction of the vector force is

$v_1=(1-0)\hat i+(1-0)\hat j +(0-0)\hat k\\\\=1\hat i+1\hat j+0\hat k\\\\=\hat i + \hat j$

The unit vector in the direction of force will be

$\frac{v_1}{|v_1|} =\frac{\hat i+ \hat j}{\sqrt{1^2+1^2+0^2} } \\\\=\frac{1}{\sqrt{2} (\hat i +\hat j)}$

The magnitude of the force is 40lb, so the force will be

$F_1=40\times \frac{1}{\sqrt{2} } (\hat i+\hat j)\\\\=20\sqrt{2} (\hat i+\hat j)$

The terminal point of its vector is point Q(0, 1, 1)

Therefore, the direction of the vector force is

$v_2=(0-0)\hat i+(1-0)\hat j +(1-0)\hat k\\\\=0\hat i+1\hat j+1\hat k\\\\=\hat j + \hat k$

$\frac{v_2}{|v_2|} =\frac{\hat j+ \hat k}{\sqrt{0^2+1^2+1^2} } \\\\=\frac{1}{\sqrt{2} (\hat j +\hat k)}$

The magnitude of the force is 60lb, so the force will be

$F_2=60\times \frac{1}{\sqrt{2} } (\hat j+\hat k)\\\\=30\sqrt{2} (\hat j+\hat k)$

The resultant of the two forces is

$F=F_1+F_2\\\\=[20\sqrt{2} (\hat i+\hat j)]+[30\sqrt{2} (\hat j +\hat k)]\\\\=20\sqrt{2} \hat i+20\sqrt{2} \hat j +30\sqrt{2} \hat j+30\sqrt{2} \hat k\\\\=20\sqrt{2} \hat i+50\sqrt{2} \hat j+30\sqrt{2} \hat k$

The magnitude force will be

$|F|=\sqrt{(20\sqrt{2} )^2+(50\sqrt{2} )^2+(30\sqrt{2} )^2} \\\\=\sqrt{800+5000+1800} \\\\=\sqrt{3100} \\\\=55.68$

to (1 decimal place)=55.7lb

b) The direction angle of force F

The angle formed by F and x axis

$\alpha=\cos^{-1}(\frac{20\sqrt{2} }{\sqrt{3100} } )\\\\=\cos^{-1}(0.5080)\\\\=59.469$

The angle formed by F and y axis

$\alpha=\cos^{-1}(\frac{50\sqrt{2} }{\sqrt{3100} } )\\\\=\cos^{-1}(1.270)\\\\=$

The angle formed by F and z axis

$\alpha=\cos^{-1}(\frac{30\sqrt{2} }{\sqrt{3100} } )\\\\=\cos^{-1}(0.7620)\\\\=40.359$

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1 year ago

Last year Beth's annual salary was $38,350. This year she received a promotion and now earns $46,462 annually. She is paid biwee

kenny6666 [7]

Answer:

Quite simple. There are 52 weeks in a year. She gets paid 26 times, every other week.

38,350 / 26 = her salary from last year per check.

46,462 / 26 = her new salary per check

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1 year ago

On January 1, year 1, Klondike issued 10-year bonds with a stated rate of 10% and a face amount of $100,000. The bonds pay inter

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Answer:

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Step-by-step explanation:

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AlladinOne [14]

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faltersainse [42]

Answer:

6(4x-1) is equivalent to 24x-6 and (2*12x)-(2*3)

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Step-by-step explanation:

An equivalent expression is an expression which either simplified or factored is equal to it.

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2 years ago