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2 years ago

Solve for a. 7a-2b = 5a b

Mathematics

2 answers:

Nookie1986 [14]2 years ago

8 0

For this case we have the following expression:

$7a-2b = 5ab$

From here, we must clear the value of a.

We then have the following steps:

Place the terms that depend on a on the same side of the equation:

$7a - 5ab = 2b$

Do common factor "a":

$a (7 - 5b) = 2b$

Clear the value of "a" by dividing the factor within the parenthesis:

$a =\frac{2b}{7-5b}$

Answer:

The clear expression for "a" is given by:

$a =\frac{2b}{7-5b}$

Fittoniya [83]2 years ago

8 0

Answer: The required value of a is $\dfrac{2b}{7-5b}.$

Step-by-step explanation: We are given to solve the following equation for the value of a:

$7a-2b=5ab~~~~~~~~~~~~~~~~~~~~~(i)$

Since there are two unknowns and only one equation , so the value of a will definitely contain the value of b.

The solution of equation (i) for a is as follows:

$7a-2b=5ab\\\\\Rightarrow 7a-5ab=2b\\\\\Rightarrow a(7-5b)=2b\\\\\Rightarrow a=\dfrac{2b}{7-5b}.$

Thus, the required value of a is $\dfrac{2b}{7-5b}.$

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Answer:

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Step-by-step explanation:

If the height is 3 times the diameter, it is 6 times the radius. Then the volume is ...

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The lateral area of the cone is computed from the slant height. For this cone, the slant height is found using the Pythagorean theorem:

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2 years ago

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2 years ago

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2 years ago

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2 years ago

One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples

JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11$

$t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708$

[(82.3-81.2) ± 1.708* (6.11* $\sqrt{\frac{1}{15}+\frac{1}{12} }$ ]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

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2 years ago