We can used the Simpson's Rule says to approximate the area under a given curve using the following formula:
<span>(Δx/3)[f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + ... + 2f(xn-2) + 4f(xn-1) + f(xn)] </span>
<span>The pool is divided into 8 subintervals. We integrate the given function from 0 to 24, while the graph provides values of f(x) at 7 different points. The first value given, 6.2, is NOT f(0). It is f(3). Using Simpson's Rule, and dividing the lake of 24 meters into 8 subintervals, we write the equation: </span>
<span>area = (3/3)[f(0) + 4f(3) + 2f(6) + 4f(9) +2f(12) + 4f(15) + 2f(18) + 4f(21) + f(24)] </span>
<span>Pool area = 0 + 4(6.2) + 2(7.2) +4(6.8) + 2(5.6) + 4(5.0) +2(4.8) +4(4.8) + 0 = 126.4 m^2 </span>
<span>Rounding to the nearest square meter, the area of the lake is approximately 126 m^2 </span>
Answer:
1.65 + 0.09s
Step-by-step explanation:
Given that :
Cost of speaker = $22
Cost per song = $1.25
Sales tax rate = 7.5%
Expression to obtain the amount of sales tax on entire purchase : 0.075(22 + 1.25s)
Expanding the expression :
0.075(22 + 1.25s)
(0.075 * 22) + (0.075 * 1.25s)
1.65 + 0.09375s
Rounding to the nearest hundredth :
Sales tax on entire purchase :
1.65 + 0.09s
J(jeans) = 2s + 4
d(dress pants) = 2.5s - 2
s = shirt
he spent : 2s + 4 + 2.5s - 2 = 4.5s + 2
Answer:
4.79$ for each mug
Step-by-step explanation:
38.32/8 = 4.79 and to double-check do 4.79*8
Answer:
142.2 meters.
Step-by-step explanation:
We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.
Let us find total surface area of box using surface area formula of cuboid.
, where,
= Length of cuboid,
= Breadth of cuboid,
= Width of cuboid.




Therefore, the total surface area of box will be 7584 square cm.
To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.





Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.




Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.