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2 years ago

A and b are natural numbers. The diameter of cell a is 2.3 , and the diameter of cell b is 2.3 .

Mathematics

2 answers:

Pani-rosa [81]2 years ago

8 0

After clarification we see the respective diameters are

$A = 2.3 \times 10^{-a}$

$B = 2.3 \times 10^{-b}$

We're asked about the ratio

$A:B = 2.3 \times 10^{-a} : 2.3 \times 10^{-b} = 10^{-a} : 10^{-b} = 10^b : 10^a = 10^{b-a} : 1$

Now we can go through the choices.

A. If a = 4 and b = 6, then cell a is 100 times greater than cell b.

$A:B=10^{6-4}:1 = 100:1$

It would be more proper to say the diameter of cell A is 100 times the diameter of cell B, but yes, this is TRUE.

B. If a = 4 and b = 6, then cell b is 100 times greater than cell a.

FALSE. 10 to the minus 4 is 100 times bigger than 10 to the minus 6, so a is bigger.

C. If a = 4 and b = 6, then cell a is 2 times greater than cell b.

FALSE. We already calculated its 100 times bigger.

D. If a = 4 and b = 6, then cell b is 2 times greater than cell a.

FALSE.

Svetlanka [38]2 years ago

8 0

Answer:

A. If a = 4 and b = 6, then cell a is 100 times greater than cell b.

Step-by-step explanation:

2.3/2.3= 1

10(-4)/10(-6)=10(2)

your answer is 100, cell a is 100 times greater than cell b.

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2 years ago

Students are going through a three-step process to obtain their ID cards. Each student will spend 2 minutes at the registration

kondaur [170]

Answer:

C. 160 minutes

Step-by-step explanation:

The calculation to be made will be to process 20 students

We have, according to the exercise, the following data:

For process 1: Registration table, Number of servers = 1, Time spent = 2 minutes

For process 2: cashier, number of servers = 3, time spent = 10 minutes

For process 3: ID processing station, number of servers = 4, time spent = 20 minutes

Demand rate = 0.125

To solve it, we will look for the capacity that the server has of the previously mentioned processes, calculating the following:

Capacity = Number of students served per minute

We can say that at the registration table we observe:

Time needed to serve 1 student = 2 minutes

Capacity = 0.5 students per minute

With the cashier we analyze the following:

Time needed to serve 1 student = 10 minutes

Number of servers = 3

Capacity = 0.3 students per minute

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Time needed to serve 1 student = 20 minutes

Number of servers = 4

Capacity = 0.2 students per minute

When comparing the processes, it is definitely found that the bottleneck is the ID processing station, where it takes more time to serve a student, which leads us to infer that the capacity of the process is comparable to the capacity of the process bottleneck

Process capacity = 0.2 students per minute

Given, demand rate = 0.125 students per minute

We observe that the demand rate is less than the capacity of the process, therefore we can infer that the number of students served during each minute is the same as the demand rate.

In this way we find that:

Number of students served per minute = 0.125

Time needed to serve 1 student = 1 / 0.125 = 8 minutes

Time needed to serve 20 students = 8 x 20 = 160 minutes.

We conclude that the answer is that it will take 160 minutes to serve 20 students.

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2 years ago

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Point AAA is at {(6,1)}(6,1)left parenthesis, 6, comma, 1, right parenthesis and point CCC is at {(2,-7)}(2,−7)left parenthesis,

pychu [463]

Answer:

The coordinates of B is (3, - 5)

Step-by-step explanation:

A(6, 1)

C(2, -7)

Coordinates of point B such that AB = 1/3 × BC

Hence we have;

$AC = AB + BC = BC + \dfrac{1}{3} \times BC = \dfrac{4}{3} \times BC$

Therefore BC = 3/4 × AC

Hence, AB = 1/3 × BC = 1/3 × 3/4 × AC = 1/4 × AC

AC = √((6 - 2)² + (1 - (-7))²) = √(16 + 64) = √80 = 4·√5

AB = 1/4 × 4·√5 = √5

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AB² = (x - 6)² + (y - 1)² = 5

Slope = (1 - (-7))/(6 - 2) = 2

Hence the y coordinate of B = -7 + sin(tan⁻¹(2)) ×√5 = -5

The x coordinate of B = 2 + cos(tan⁻¹(2)) ×√5 = 3

The coordinates of B = (3, - 5)

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