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guapka [62]
2 years ago
12

A survey of one class at Pioneer Middle School found that 20 out of 30 students would spend $12 for a school t-shirt Suppose the

re are 600 students in the school how many students do you predict would spend $12 for a school t-shirt
Mathematics
2 answers:
olchik [2.2K]2 years ago
7 0

Answer:

The answer is 400

Step-by-step explanation:


Virty [35]2 years ago
4 0
\frac{20}{30} = \frac{x}{600}
600/30=20.
20*20=400.
Your answer is 400.
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Linda Gramham's Cinnamon Sugar Graham Cupcake recipe for 36 cupcakes requires 1 1/4 cups of sugar. How much sugar is required fo
Anon25 [30]

Answer:

31.25 or 31  1/4 cups

Step-by-step explanation:

1  1/4 = 36

x = 900

=> 5/4 = 36

    x = 900

Cross multiply

=> 5/4 * 900 = 36 * x

=> 4500/4 = 36x

=> 1125 = 36x

=> 1125 / 36 = 36x / 36

=> 31.25 = x

31.25 = 31  1/4

So, 31.25 or 31 1/4 cups are required for 900 cupcakes.

5 0
2 years ago
The area of an extra large circular pizza from Gambino's Pizzeria is 484\pi \text{ cm}^2484π cm 2 484, pi, space, c, m, start su
oksano4ka [1.4K]

Answer:

The diameter of an extra large pizza from Gambino's Pizzeria is 44\ cm

Step-by-step explanation:

we know that

The area of a circle (circular pizza ) is equal to

A=\pi r^{2}

we have

A=484\pi\ cm^{2}

substitute in the formula and solve for the radius r

484\pi=\pi r^{2}

Simplify

484=r^{2}

r=22\ cm

Find the diameter

Remember that the diameter is two times the radius

D=2(22)=44\ cm

3 0
2 years ago
Read 2 more answers
At a breakfast buffet, 54% of people choose coffee for their beverage while 16% choose juice. Also, 12% choose both coffee and j
AnnZ [28]

Answer:

I'm gonna have to say 54%.

Step-by-step explanation:

It says right in the question, "At a breakfast buffet, 54% of people choose coffee for their beverage"

3 0
2 years ago
Read 2 more answers
A given set of values is found to be a normal distribution with a mean of 140 and a standard deviation of 18.0. Find the value t
Alisiya [41]

Answer:

The value that is greater than 45% of the data values is approximately 137.84.

Step-by-step explanation:

The key is transforming values from this distribution to a z-score range and finding the corresponding value using a z-score table.

We are looking for a value x which attains a critical z-score that corresponds to the (100-45)%=55-th percentile:

z_{0.55} = \frac{x-\mu}{\sigma}=\frac{x-140}{18}\implies x = 18\cdot z_{0.55}+140

The critical z value (from z-score table, online) is: -0.12, so:

x = 18\cdot z_{0.55}+140=18\cdot(-0.12)+140\approx137.84

The value that is greater than 45% of the data values is approximately 137.84.


5 0
2 years ago
Read 2 more answers
Rhian sat a Maths test and an English test.
stiks02 [169]
She scored better with math
7 0
2 years ago
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