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Monica [59]
1 year ago
6

Zach read a book for 10 minutes every weekend in the first month, 20 minutes in the second month, 40 minutes in the third month,

and 80 minutes in the fourth month. Victoria read a book for 35 minutes every weekend in the first month, 50 minutes in the second month, 65 minutes in the third month, and 80 minutes in the fourth month. Which statement best describes the methods used by Zach and Victoria to increase the time they spent reading a book? A) Zach's method is linear because the number of minutes increased by an equal factor every month. B) Victoria's method is linear because the number of minutes increased by an equal number every month. C) Both Victoria and Zach's method is exponential because the number of minutes increased by an equal factor every month. D) Both Victoria and Zach's method is exponential because the number of minutes increased by an equal number every month.
Mathematics
2 answers:
pogonyaev1 year ago
7 0
"Victoria's method is linear because the number of minutes increased by an equal number every month" is the method that <span>best describes the methods used by Zach and Victoria to increase the time they spent reading a book. The correct option among all the options that are given in the question is the second option or option "B".</span>
den301095 [7]1 year ago
5 0
Zach time of reading every weekend forms a sequence with these terms: 10, 20, 40, 80. On the other hand, that of Victoria forms a sequence with terms: 35, 50, 65, 80. By keenly observing the sequences, Zach's sequence is a geometric sequence with a common ratio equal to 2 and Victoria's sequence is an arithmetic or linear sequence with a common difference of 15. Thus, the answer is letter B.
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Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

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Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



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