Question

Which of the following completes the proof? Triangles ABC and EDC are formed from segments BD and AC, in which point C is between points B and D and point E is between points A and C. Given: Segment AC is perpendicular to segment BD Prove: ΔACB ~ ΔECD Reflect ΔECD over segment AC. This establishes that ________. Then, ________. This establishes that ∠E'D'C' ≅ ∠ABC. Therefore, ΔACB ~ ΔECD by the AA similarity postulate. ∠ABC ≅ ∠E'D'C'; translate point E' to point A ∠ACB ≅ ∠E'C'D'; translate point E' to point B ∠ACB ≅ ∠E'C'D'; translate point D' to point B ∠ABC ≅ ∠E'D'C'; translate point D' to point A

Answer 1

Answer:

∠ACB ≅ ∠E'C'D'. translate point E' to point A

Step-by-step explanation:

Answer 2

Answer: ∠ACB ≅ ∠E'C'D'; translate point D' to point B

Step-by-step explanation:

That is just my best guess.