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nasty-shy [4]
1 year ago
8

a basketball costs $15.00. if the sales tax is 6%, witch equation can be used to find the amount of tax

Mathematics
2 answers:
d1i1m1o1n [39]1 year ago
7 0
$15 * .06= tax
or $15(.06)= tax

just multiply the price by the decimal form of the sales tax to get the tax amount.
Neko [114]1 year ago
6 0
U can use 15.00 ti,es 6
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Bonny Blair of the United States set a world record in speed skating when
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Answer:

4589.75J

Step-by-step explanation:

Kinetic energy = 1/2 x M x v^2

Given

Mass M = 55.0kg

V = 12.92m/s

Kinetic energy

= 1/2 x 55.0 x (12.92)^2

= 1/2 x 55.0 x (12.92 x 12.92)

= 1/2 x 55.0 x 166.9

Multiply through

= 9179.5/2

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7 0
1 year ago
silvia compro la misma licuadora que daniela, que costaba $355.5, pero como abonó con tarjeta de credito, le recargaron un 16%,
Debora [2.8K]

Answer:

Costo final= $412.38

Step-by-step explanation:

Dada la siguiente información:

Costo inicial= $355.5

Recargo de la tarjeta= 16% = 0.16

<u>Para calcular el costo final que debe pagar Silvia, debemos usar la siguiente información:</u>

Costo final= costo inicial*(1 + recargo)

Costo final= 355.5*1.16

Costo final= $412.38

4 0
1 year ago
6 ice cream cones cost $10. How much does 9 cost
icang [17]
$15.00 hope this helps!
3 0
1 year ago
Read 2 more answers
The number of people who attended a concert on Friday was 3/4 the number of people who attended the same concert on Saturday. A
LiRa [457]

On Saturday, 4/4 of the amount of people attended.  On Friday, 3/4 of the amount on Saturday attended.  We have 7 parts (3 from Friday and 4 from Saturday).

840/7 = 120.

Thus, 360 people attend on Friday and 480 on Saturday.

8 0
1 year ago
A study was performed on green sea turtles inhabiting a certain area.​ Time-depth recorders were deployed on 6 of the 76 capture
polet [3.4K]

Answer:

One can be 99% confident the true mean shell length lies within the above interval.

The population has a relative frequency distribution that is approximately normal.

Step-by-step explanation:

We are given that Time-depth recorders were deployed on 6 of the 76 captured turtles. These 6 turtles had a mean shell length of 51.3 cm and a standard deviation of 6.6 cm.  

The pivotal quantity for a 99% confidence interval for the true mean shell length is given by;

                    P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean shell length = 51.3 cm

             s = sample standard deviation = 6.6 cm

             n = sample of turtles = 6

             \mu = true mean shell length

Now, the 99% confidence interval for \mu =  \bar X \pm t_(_\frac{\alpha}{2}_)  \times \frac{s}{\sqrt{n} }

Here, \alpha = 1% so  (\frac{\alpha}{2}) = 0.5%. So, the critical value of t at 0.5% significance level and 5 (6-1) degree of freedom is 4.032.

<u>So, 99% confidence interval for</u> \mu  =  51.3 \pm 4.032 \times \frac{6.6}{\sqrt{6} }

                                                         = [51.3 - 10.864 , 51.3 + 10.864]

                                                         = [40.44 cm, 62.16 cm]

The interpretation of the above result is that we are 99% confident that the true mean shell length lie within the above interval of [40.44 cm, 62.16 cm].

The assumption about the distribution of shell lengths must be true in order for the confidence interval, part a, to be valid is that;

C. The population has a relative frequency distribution that is approximately normal.

This assumption is reasonably satisfied as the data comes from the whole 76 turtles and also we don't know about population standard deviation.

3 0
1 year ago
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