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Eddi Din [679]
2 years ago
12

Rewrite the proportion 7:21 = 3:9 as a proportion using fractions.

Mathematics
2 answers:
Fudgin [204]2 years ago
8 0
A :) hope that helped
Margarita [4]2 years ago
3 0

Answer:

a

Step-by-step explanation:

7/21=3/9 bc why would it be anything else?

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The manager at Gabriela's Furniture Store is trying to figure out how much to charge for a book shelf that just arrived. The boo
BigorU [14]

Answer:

thy should sell it for $235.2 because in the shop they sell everything for 60% the original price for which they bought it

Step-by-step explanation:

4 0
2 years ago
The organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 e
ki77a [65]

Let s represent number of shirts and h represent number of hats.

We have been given that the organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 each and hats for $8 each.

The cost of s shirts would be 10s and cost of h hats would be 8h. The cost of s shirts and h hats should be less than or equal to 1800. We can represent this information in an inequality as:

10s+8h\leq 1800

We are also told that organizers plan to buy at least 5 times as many shirts as hats. This means that number of shirts should be greater than or equal to 5 times hats. We can represent this information in an inequality as:

s\geq 5h

Therefore, the second inequality should be s\geq 5h and option C is the correct choice.

6 0
2 years ago
James thinks of two numbers. He says "The Highest Common Factor (HCF) of my two numbers is 3 The Lowest Common Multiple (LCM) of
xxTIMURxx [149]

Answer: (3,45) and (15,9)

Step-by-step explanation:

LCM x HCF = 45*3 = 135

so, the pairs which has HCF as 3 and LCM as 45 are (3,45) and (15,9)

5 0
1 year ago
M and N are two events P(M) = 0.60, P(N) = 0.20, and P (M and N) = 0.1.
saul85 [17]

Answer:

.7

Step-by-step explanation:

i just took the test :)

8 0
1 year ago
Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies weig
Anon25 [30]

Answer:

3.84% probability that it has a low birth weight

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3466, \sigma = 546

If we randomly select a baby, what is the probability that it has a low birth weight?

This is the pvalue of Z when X = 2500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2500 - 3466}{546}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384

3.84% probability that it has a low birth weight

3 0
2 years ago
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