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Eddi Din [679]
2 years ago
12

Rewrite the proportion 7:21 = 3:9 as a proportion using fractions.

Mathematics
2 answers:
Fudgin [204]2 years ago
8 0
A :) hope that helped
Margarita [4]2 years ago
3 0

Answer:

a

Step-by-step explanation:

7/21=3/9 bc why would it be anything else?

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5 0
1 year ago
Rate at which risk of down syndrome is changing is approximated by function r(x) = 0.004641x2 − 0.3012x + 4.9 (20 ≤ x ≤ 45) wher
romanna [79]
The rate of change of the risk of down syndrome (in percentage of births per year) is
r(x) = 0.004641x² - 0.3012x + 4.9,   20≤ x ≤ 45
where
x = maternal age at delivery.

The function giving risk as a percentage of births when maternal age is x is the integral of r(x). That is,
f(x) = 0.001547x³ - 0.1506x² +4.9x + c

When x = 30, f = 0.14%. Therefore
0.001547(30³) - 0.1506(30²) + 4.9(30) + c = 0.14 
41.769 - 135.54 + 147 + c = 0.14
c = -53.089

Answer:
f(x) = 0.001547x³ - 0.1506x² + 4.9x - 53.089,   20 ≤ x ≤ 45

The function is graphed as shown below.

7 0
2 years ago
If sin 150° is 1/2 find sin75°
lisabon 2012 [21]

Answer:

use a calculator and enter those numbers then press SIN

Step-by-step explanation:

7 0
2 years ago
Alejandra's Tapas Bar offers a menu consisting of $9$ savory and $5$ sweet dishes. You can also get a mix-and-match plate consis
Mariana [72]

Answer:

45

Step-by-step explanation:

Given that the number of savory dishes is 9 and the number of sweet dished is 5.

Denoting all the 9 savory dishes by p_1, p_2,...,p_9, and all the sweet dishes by q_1,q_2,...,q_5.

The possible different mix-and-match plates consisting of two savory dishes are as follows:

There are 9 plates with q_1 from sweet plates which are (q_1, p_1), (q_1, p_2), ..., (q_1,p_9).

There are 9 plates with q_2 from sweet plates which are  (q_2, p_1), (q_2, p_2), ..., (q_2,p_9).

Similarly, there are 9 plated for each q_3, q_4 and q_5.

Hence, the total number of the different mix-and-match plates consisting of two savory dishes

= 9+9+9+9+9= 9\times5=45

7 0
2 years ago
Which are the solutions of x2 = 19x + 1?
Finger [1]

Answer:

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

Step-by-step explanation:

we have

x^2=19x+1

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2}-19x-1=0  

so

a=1\\b=-19\\c=-1

substitute in the formula

x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}

x=\frac{19\pm\sqrt{365}} {2}

x=\frac{19+\sqrt{365}} {2}

x=\frac{19-\sqrt{365}} {2}

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0
2 years ago
Read 2 more answers
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