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Aliun [14]
1 year ago
9

A computer store sells computers for 10% more than they pay for them. If the store pays x dollars for a computer, which expressi

on would represent the price the store would sell the computer at?
Mathematics
2 answers:
nadya68 [22]1 year ago
6 0

Answer:

x-0.10x

Step-by-step explanation:

Olenka [21]1 year ago
4 0

Answer: what

Step-by-step explanation:

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In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE ║ AB . If m∠ADE is with 34° smaller than m∠CAB, find the measures
Charra [1.4K]

Answer:

34°

Step-by-step explanation:

If m∠ADE is with 34° smaller than m∠CAB, then denote

m∠ADE=x°,

m∠CAB=(x+34)°.

Since  DE ║ AB, then

m∠ADE=m∠DAB=x°.

AD is angle A bisector, then

m∠EAD=m∠DAB=x°.

Thus,

m∠CAB=m∠CAD+m∠DAB=(x+x)°=2x°.

On the other hand,

m∠CAB=(x+34)°,

then

2x°=(x+34)°,

m∠ADE=x°=34°.

7 0
2 years ago
40 POINTS!!!!! A submarine descends to 1/6 of its maximum depth. Then it descends another 2/3 of its maximum depth. If it is now
tia_tia [17]
Its max is 780

2/3 + 1/6 = 5/6

650/5=130

650+130=780
4 0
2 years ago
Evaluate e − 1 2 f e− 2 1 ​ fe, minus, start fraction, 1, divided by, 2, end fraction, f when e = 15 e=15e, equals, 15 and f = 2
ivolga24 [154]
The answer 456 fe
Because it the benefit is doing today
7 1
2 years ago
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How many terms are in the algebraic expression Negative 7 + 12 x 4 minus 5 y 8 + x?
BARSIC [14]

Answer:

Therefore,

There are Four i.e 4 terms in the expression,

-7+12x^{4}-5y^{8}+x

Step-by-step explanation:

Algebraic Expression:

An algebraic expression is a mathematical expression that consists of variables, numbers and operations.

  • Variables with the coefficient is called as Term.
  • Number is also a term.

Here the Expression is

-7+12x^{4}-5y^{8}+x

So,

-7 = One\ Term\\12x^{4}=Second\ Term\\-5y^{8}=Third\ Term\\x=Fourth\ Term

In all there are Four i.e 4 terms in the given expressions.

Therefore,

There are Four i.e 4 terms in the expression,

-7+12x^{4}-5y^{8}+x

5 0
2 years ago
Read 2 more answers
Find the value of cosAcos2Acos3A...........cos998Acos999A where A=2π/1999
Lady bird [3.3K]
Hello,

Here is the demonstration in the book Person Guide to Mathematic by Khattar Dinesh.

Let's assume
P=cos(a)*cos(2a)*cos(3a)*....*cos(998a)*cos(999a)
Q=sin(a)*sin(2a)*sin(3a)*....*sin(998a)*sin(999a)

As sin x *cos x=sin (2x) /2

P*Q=1/2*sin(2a)*1/2sin(4a)*1/2*sin(6a)*....
         *1/2* sin(2*998a)*1/2*sin(2*999a) (there are 999 factors)
= 1/(2^999) * sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
 as sin(x)=-sin(2pi-x) and 2pi=1999a

sin(1000a)=-sin(2pi-1000a)=-sin(1999a-1000a)=-sin(999a)
sin(1002a)=-sin(2pi-1002a)=-sin(1999a-1002a)=-sin(997a)
...
sin(1996a)=-sin(2pi-1996a)=-sin(1999a-1996a)=-sin(3a)
sin(1998a)=-sin(2pi-1998a)=-sin(1999a-1998a)=-sin(a)

So  sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
= sin(a)*sin(2a)*sin(3a)*....*sin(998)*sin(999) since there are 500 sign "-".

Thus
P*Q=1/2^999*Q or Q!=0 then
P=1/(2^999)

       








7 0
1 year ago
Read 2 more answers
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