Answer:
Step-by-step explanation:
In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.
In the second case we'd also subtract 1 from both sides, and would obtain
|x-1|>14.
What would the graphs look like?
In the first case, the graph would be on the x-axis with "center" at x=1. From this center count 14 units to the right, and then place a circle around that location (which would be at x=15). Next, count 14 units to the left of this center, and place a circle around that location (which would be -13). Draw a line segment connecting the two circles. Notice that all of the solutions are between -13 and +15, not including these endpoints.
In the second case, x has to be greater than 15 or less than -13. Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right. None of the values in between are solutions.
Answer:
The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).
Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:
-6/4 + 1/4 = -5/4.
Now i will give some other examples:
Now, if the distance between ticks is 2/4, then the number at the right will be:
-6/4 + 2/4 = -4/4 = -1
Now, if the distance between ticks is 3/4, the the number at the right will be:
-6/4 + 3/4 = -3/4.
So, basically ..you just multiply
9*9*9*9
6561
