Help!!! i need to get an A!!!

Assume the returns from an asset are normally distributed. The average annual return for the asset is 17.4 percent and the stand

Jlenok [28]

Answer:

0.13%

Step-by-step explanation:

Mean, u = 17.4%

standard deviation, sd = 27.5%

We are looking for the probability that the money will double in value. Therefore we are looking for the value of x = 100% (meaning the value is 100% more that the previous year)

Find the value of z-score

z = (x-u)/sd

= (100 - 17.4) / 27.5 = 3.003

Find the z score using the z-table

From z-table at P(z<3.003) = 0.9987

So, for the probability that it the money will be double is

P (Z>2.8982) = 1 - P(z<2.8982)

= 1- 0.9987

= 0.0013 = 0.13%

6 0

2 years ago

If point C is inside AvB, then __+m CvB= m AvB

adelina 88 [10]

Answer: OPTION A

Step-by-step explanation:

It is important to remember the "Angle Addition Postulate" in order to solve this exercise.

You have this larger angle:

$\angle AVB$

According to the "Angle Addition Postulate", if the point "C" is in the interior of $\angle AVB$ , then the measure of this angle can be obtained by adding the angle $\angle AVC$ and the angle $\angle CVB$ .

You can observe in the figure that:

$m\angle AVC=39\°\\\\\mangle CVB=23\°$

Then you get that:

$m\angle AVC+m\angle CVB=m\angle AVB\\\\39\°+23\°=62\°$

Therefore, the correct answer is Option A.

3 0

2 years ago

Read 2 more answers

The mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of

grandymaker [24]

Answer:

At the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Step-by-step explanation:

We are given that the mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000.

The ship building association wishes to find out whether their welders earn more or less than $20,000 annually.

Let $\mu$ = mean gross annual incomes of certified welders

So, Null Hypothesis, $H_0$ : $\mu$ = $20,000

Alternate hypothesis, $H_A$ : $\mu \neq$ $20,000

Here, null hypothesis states that the mean income of welders is equal to $20,000.

On the other hand, alternate hypothesis states that the mean income of welders is not $20,000.

Also, the test statistics that would be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean income

$\sigma$ = population standard deviation = $2,000

n = sample size

Now, at the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

3 0

2 years ago

The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio

zzz [600]

Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

a)

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

b)

i) SD = 0.65

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

c)

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

d)

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

4 0

2 years ago

Which graph represents the function f(x) = -|x+3|?

Fofino [41]

The last one is correct

5 0

2 years ago

Read 2 more answers