If there are no notebooks purchased, then Eula may buy 5 binders. If no binders are bought, then Eula may buy 10 notebooks. If 7 notebooks are purchased, then one binder may be purchased; this will also cause Eula to have $2 extra (maybe for tax).
Answer:
Step-by-step explanation:
given is the Differential equation in I order linear as
Take Laplace on both sides
![L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}](https://tex.z-dn.net/?f=L%28y%27%29%20%2B4L%28y%29%20%3D%2048L%28t%29%5C%5CsY%28s%29-y%280%29%20%2B4Y%28s%29%20%3D%2048%20%2A%5Cfrac%7B1%7D%7Bs%5E2%7D%20%5C%5CY%28s%29%20%5Bs%2B4%5D%3D%5Cfrac%7B48%7D%7Bs%5E2%7D%2B9%5C%5CY%28s%29%20%3D%20%5Cfrac%7B1%7D%7Bs%5E2%28s%2B4%29%7D%2B%5Cfrac%7B9%7D%7Bs%2B4%7D)
Now if we take inverse we get y(t) the solution
Thus the algebraic equation would be
The band sold 33 single CDs and 19 double CDs.
33 x 12 = 396
19 x 17 = 323
396 + 323 = 719
Answer:
The value of x is 10
Step-by-step explanation:
We can use a system of equations to solve this.
Cups of 25% bleach solution used = x
Cups of 1-% bleach solution used = 5
Cups of solution we get = y
The first equation becomes:
x + 5 = y
Using the decimal forms of each percentage solution
25% solution for x cups = 0.25x
10% solution for 5 cups = 0.1(5)
20% solution for y cups = 0.2 y
The second equation becomes:
0.25x + 0.1(5) = 0.2y
So the system of equations is:
x + 5 = y
0.25x + 0.1(5) = 0.2y
Solve both equations simultaneously to find the values of x and y:
x = 10 cups
y = 15 cups
Answer:
Step-by-step explanation:
a) For a prime numbers we have array with 2 rectangulars R1: a=1 and b=prime number; R2: a=prime number and b=1. Both has the same are, that prime number.
b) For a composite number which are not square number we have rectanular array with even numbers of ractangulars. For example, number 6.
R1: a=1,b=6; R2: a=2,b=3; R3: a=3, b=2; R4: a=6,b=1. Each rectangular has the same area, 6.
c) The square number we alway have te odd number of rectanulars, because of the square a=x,b=x can not be simetric. For example 16.
R1: a=1,b=16; R2: a=2 , b=8; R3: a=4,b=4; R4: a=8, b=2; R5:a=16,b=1.Each rectangular has the same area, 16.
