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docker41 [41]
2 years ago
13

Shelby mixes a 25% bleach solution with 5 cups of a 10% bleach solution, resulting in a 20% bleach solution. The table shows the

amount of each solution used. A table titled Bleach Solution showing Cups, Bleach concentration, and Total. The first row shows 10 percent Bleach with 5, 0.10, and 0.5. The second row shows, 25 percent bleach, with x, 0.25, and 0.25 x. The third row shows Mixture, with 5 plus x, 0.20, and 3. What is the value of x? 1 3 10 24
Mathematics
2 answers:
Tcecarenko [31]2 years ago
8 0

Answer:

The value of x is 10

Step-by-step explanation:

We can use a system of equations to solve this.

Cups of 25% bleach solution used = x

Cups of 1-% bleach solution used = 5

Cups of solution we get = y

The first equation becomes:

x + 5 = y

Using the decimal forms of each percentage solution

25% solution for x cups = 0.25x

10% solution for 5 cups = 0.1(5)

20% solution for y cups = 0.2 y

The second equation becomes:

0.25x + 0.1(5) = 0.2y

So the system of equations is:

x + 5 = y

0.25x + 0.1(5) = 0.2y

Solve both equations simultaneously to find the values of x and y:

x = 10 cups

y = 15 cups

vekshin12 years ago
7 0

Answer:

10

Step-by-step explanation:

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Is it possible to form a triangle with side lengths 3.5 3.5, and 9? If so, will it be scalene, isosceles, or equilateral? Or non
Charra [1.4K]

Answer:

It is not possible to draw a triangle with given measurements of 3.5, 3.5, and 9.

Step-by-step explanation:

<em><u>Scalene Triangle</u></em> - All 3 sides have different lengths.

<em><u>I</u></em><em><u>s</u></em><em><u>osceles</u></em><em><u> </u></em><em><u>Triangle</u></em> - 2 sides have equal lengths.

<em><u>Equilateral</u></em><em><u> </u></em><em><u>Triangle</u></em> - All 3 sides have equal lengths.

You must be thinking that it would be Isosceles triangle, but it is not. The measurements you gave is 3.5, 3.5, and 9. Grab a piece of paper, ruler, and a pencil. First draw the length of 9 cm with your pencil and ruler (let us pretend that the measurements are in cm). Then draw 3.5 cm by placing your ruler on the end/start of your 9cm line that you drew before. Then, once again draw a 3.5 cm on the other end of the 9cm line. You will see something like the picture above. You can see that the two sides of the triangle are not intersecting on the top. This means that the triangle formation cannot be made by the given measurements of 3.5, 3.5, and 9.

I hope you understand my answer and this is an easy way to find if, from the given measurements, a triangle is able to be drawn. Thank you !!

4 0
1 year ago
Alison is saving for retirement. Her company matches what she puts into her 401K in a ratio of 2:3. If she puts in $400 each mon
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Id say B...............
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2 years ago
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In an inventory of 100 sodas, 65 are
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Answer:

5% I think

Step-by-step explanation:

Its mostly just a guess but I think its 5%

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2 years ago
Find the dimensions of a deck which will have railings on only three sides. There is 28 m of railing available and the deck must
Roman55 [17]

Answer:

The largest possible area of the deck is 87.11 m² with dimensions;

Width = 9.33 m

Breadth = 9.33 m

Step-by-step explanation:

The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square

Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area

The length of the given railing = 28 m

The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each

The area of a square of side s = s²

The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;

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5 0
2 years ago
Solve the following quadratic equations by extracting square roots.Answer the questions that follow.
Vikentia [17]

Answer:

1.  x=±4

2. t=±9

3. r=±10

4. x=±12

5. s=±5

Step-by-step explanation:

1. x^2 = 16

Taking square root on both sides

\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\

x=±4

2. t^2=81

Taking square root on both sides

\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}

t=±9

3. r^2-100=0

r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}

r=±10

4. x²-144=0

x²=144

Taking square root on both sides

\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}

x=±12

5. 2s²=50

\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}

s=±5 ..

4 0
1 year ago
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