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fenix001 [56]
1 year ago
9

Rectangular arrays whose dimensions are whole numbers can be used to illustrate the factors of a number. What can be said about

the number of rectangular arrays for each of the following types of numbers?a. Prime numberb. Composite numberc. Square number
Mathematics
1 answer:
natali 33 [55]1 year ago
6 0

Answer:

Step-by-step explanation:

a) For a prime numbers we have array with 2 rectangulars R1: a=1 and b=prime number; R2: a=prime number and b=1. Both has the same are, that prime number.

b) For a composite number which are not square number we have rectanular array with even numbers of ractangulars. For example, number 6.

R1: a=1,b=6; R2: a=2,b=3; R3: a=3, b=2; R4: a=6,b=1. Each rectangular has the same area, 6.

c) The square number we alway have te odd number of rectanulars, because of the square a=x,b=x can not be simetric. For example 16.

R1: a=1,b=16; R2: a=2 , b=8; R3: a=4,b=4; R4: a=8, b=2; R5:a=16,b=1.Each rectangular has the same area, 16.

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Liono4ka [1.6K]
Perhaps the easiest way to solve this problem is to convert 13 into a fraction that has the same denominator as 7 5/8.
Convert both to improper fractions:
7 5/8 turns into 61/8, and
13 turns into 104/8.

Then, subtract 61/8 from 104/8:
104/8-61/8=43/8.
Simplify (mixed fraction):
5 3/8.

The second ribbon has a length of 5 3/8 meters.

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2 years ago
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In a certain recipe that produces enough for 8 servings, 1/2 cup of sugar is required. If you were asked to expand this recipe s
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We have to apply the rule of three

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Circle A and circle B are congruent. CD is a chord of both circles. If AB = 8 ft and CD = 6 ft, how long is a radius?
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Let us say that the intersection point of lines AB and CD is called point E. The lines AB and CD are perpendicular to each other which also means that the triangle CEB is a right triangle.

Where the line CB is the radius of the circle while the side lengths are half of the whole line segment:

EB = 0.5 AB = 0.5 (8 ft) = 4 ft

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Now using the hypotenuse formula since the triangle is right triangle, we can find for the radius or line CB:

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<span>CB = 5 ft = radius</span>

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