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2 years ago

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The equation cos super negative 1 (StartFraction 3.4 Over 10 EndFraction)equals x can be used to determine the measure of angle

BAC.
Triangle A B C is shown. Angle A C B is a right angle. The length of hypotenuse A B is 10 centimeters and the length of A C is 3.4 centimeters. Angle C A B is x.

What is the degree measure of angle BAC? Round to the nearest whole degree.

19°

20°

70°

71°

2 answers:

gizmo_the_mogwai [7]2 years ago

8 0

Answer: the anwser is 70 degrees

Step-by-step explanation:

Dmitriy789 [7]2 years ago

6 0

Answer:

70 degrees

Step-by-step explanation:

$cos^{-1} \frac{3.4}{10}=x$

This implies that: $cos x= \frac{3.4}{10}$ Recall: $cos x=\frac{adjacent}{hypotenuse}$

From the diagram

Angle CAB, $x=cos^{-1} \frac{3.4}{10}=70.1 degrees$ =70 (to the nearest degree)

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Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim

vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

$2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}$

Dividing we get,

$2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}$

Adding, we have,

$2 { h } 54 \text { min }=2.9 {h}$

Thus, the total time taken by Joshua is $2.9 {h}$

To determine the average speed we use the formula,

$speed=\frac{distance}{time}$

where $distance=7250$ and $time=2.9$

Hence, substituting the values we have,

$speed=\frac{7250}{2.9}$

Dividing, we get,

$speed=2500$

Thus, the average speed of Joshua during that time is 2500 m/h.

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we can use formula

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where

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fs is siren frequency

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vs is police car speed

so, we have

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$v_p=65mph$

now, we can change it into m/s

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Step-by-step explanation:

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