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2 years ago

Which point is a solution to the inequality shown in this graph? (0,1) (3,-1)

Mathematics

2 answers:

Sonbull [250]2 years ago

6 0

All points in the shaded area are answers to the inequality. Thus you need to find the point which is in the shaded area of the graph.

Only the point (3, -1) is within range. Thus answer D is correct.

katrin2010 [14]2 years ago

3 0

Answer:

Option D, (3, -1)

Step-by-step explanation:

In the inequality shown in the graph all the points which lie above the line (in the shaded part) will be the solution.

Option A) (0, -5)

Since this point lies below the line so it is not the solution.

Option B) (0, 0)

It's below the line again therefore not the solution.

Option C) (5, -5)

It lies below the line. Therefore it is not the solution.

Option D. (3, -1)

This point lies on the line therefore satisfies the condition.

Therefore Option D. (3, -1) is the only solution.

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The measure of an angle is seventeen times the measure of a supplementary angle. What is the measure of each angle?

blagie [28]

Supplementary angles are two angles that when add equal 180 degrees.
The supplement of an angle is 180 - n.

n = 17(180 - n)
n = 3060 - 17n
n + 17n = 3060
18n = 3060
n = 3060/18
n = 170

so the unknown angle (n) = 170 degrees and its supplement = (180 - 170 = 10)......= 10 degrees.

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2 years ago

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105,159 rounded to the nearest ten thousand

ivolga24 [154]

For this case we have the following number:

105,159

By definition we have:

thousand place: five-digit number greater than zero.

On the other hand we have as a rule:

When the previous number is greater than or equal to five, then the next number increases by one.

So we have to round off to the nearest ten thousand:

105,159 = 110,000

Answer:

105,159 rounded to the nearest ten thousand is:

105,159 = 110,000

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2 years ago

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Solve the following inequality: –1 + 6(–1 – 3x) > –39 – 2x.

insens350 [35]

<span>–1 + 6(–1 – 3x) > –39 – 2x.
</span>-1-6-18x>-39-2x
-7-18x>-39-2x
-18x>-32-2x
-16x>-32
x<2

B. x<2

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There are some nickels dimes and quarters in a large piggy bank for every two nickels there are 3 dimes for every two dimes that

creativ13 [48]

We are given

piggy bank has nickels , dimes and quarters

Let's assume

number of nickels =n

every two nickels there are 3 dimes

so, number of dimes are

$=\frac{3}{2}n$

$=1.5n$

every two dimes that are 5 quarters there

so, number of quarters are

$=\frac{5}{2}\times 1.5n$

$=3.75n$

so, total number of coins = number of nickels + number of dimes +number of quarters

total number of coins =n+1.5n+3.75

there are 500 coins

so, we get

$n+1.5n+3.75n=500$

now, we can solve for n

$6.25n=500$

divide both sides by 6.25

so, we get

$n=80$

number of dimes is 1.5n

$=1.5\times 80$

$=120$

number of quarters is 3.75n

$=3.75\times 80$

$=300$

so,

Number of nickels =80

Number of dimes =120

Number of quarters =300............Answer

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2 years ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

8 0

2 years ago