Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Answer: 6.824%
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Usando conceptos de funciones lineales, se encuentra que hizo 5 cortes.
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Una funcion lineale tiene el seguiente formato:

En que:
- a eres lá inclinacion, o sea, lo que es pago por cada corte.
- b eres el intercepto, o sea, lo pagamiento fixo por día.
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- Pagan $50 por corte realizado, o sea,
. - $25 fixo al día, o sea,

Entonces, la funcion de su recibimiento y, como funcion de su numero de cortes x, es da por:

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- Recibió $275, o sea,

Entonces, el numero de cortes es:





Realizó 5 cortes.
Un problema similar se encuentra en brainly.com/question/18070326
Answer:
Area of drawing= 0.315 m²
Step-by-step explanation:
Base = 6m
Height = 4.2 m
Area = height* base
Area= 4.2*6
Area= 25.2 m²
The scale is 10 cm on the drawing for every 8 meters on the sculpture.
Which is 10 cm to 800 cm
Or
0.1m to 8m
Arra of sculpture= 25.2 m²
area of drawing= (25.2*0.1)/8
Area of drawing= 0.315 m²