<span>(serial number, model number)
That's a function mapping each serial number to its model number.
(part number, serial number)
That's not a function; the same part number is in computers with different serial numbers
</span><span> (model number, part number)
</span><span>
That one's a bit confusing. Normally a given model would have more than one part number inside so this isn't a function. But here the description says there's only one part number for each model, so that would be a function.
(model number, serial number)
Not a function, more than one serial number for a given model number.
</span>
<span> the probability that she rolls an odd number AND and pulls a red chip
so it is = Prob(odd no) * Prob(red chip)
Prob(odd no) for a fair die = 1/2
Prob(red chip) = red chip / total chip = 2/(2+1) = 2/3
so the ans is 1/2 * 2/3 = 1/3
</span>
Answer:
Expected pay winning $50= $0.585
Expected pay winning $25= $2.36
Expected pay for anything else= $-4.35
Expected returns=3.59
Expected value for one play= $(-1.41)
Do not play this game because you will lose $1.41
Step-by-step explanation:
Probability P(3 hearts) = (13/52)×(12/51)×(11/50) = 0.013
Probability P(3black)= (26/52)×(24/51)×(23/50) = 0.118
Probability P(drawing anything else)= 1 - 0.013 - 0.118= 0.869
Expected pay($50)= 0.013$(50-5)= $ 0.585
Expected pay($25)= 0.118(25-5)$ = $2.36
Expected pay for anything else= 0.869(0-5)$ =$(-4.347)
Expected value of one play=$ (0.585 + 2.353 -4.347) = -$1.41
c) Do not play the game.
The answer is C.
Note when Soro divides both sides by -2.5 to solve the equation. When multiplying/dividing by a negative number, one should always reverse the inequality sign, but Soro forgot to do this.
-2.5x≥-30
After this step, the answer SHOULD HAVE been:
x≤12
Let me know if you need any clarifications, thanks!
Before we could add these numbers, 3/8 and 7/10 need a common denominator. Both 8 and 10 go into 40.
8 goes into 40 five times
3/8= (3*5)/40 = 15/40
10 goes into 40 four times
7/10= (7*4)/40= 28/40
ANSWER: A) 15/40 and 28/40
Hope this helps! :)