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7nadin3 [17]
2 years ago
11

The traffic flow rate (cars per hour) across an intersection is r ( t ) = 400 + 800 t − 120 t 2 , where t is in hours, and t =0

is 6am. How many cars pass through the intersection between 6 am and 8 am?
Mathematics
1 answer:
Leto [7]2 years ago
3 0

Answer:

2080

Step-by-step explanation:

Given: r(t)=400+800t-120t^2

Looking for: \int\limits^{t_2}_{t_1} {r} \, dt

Solve:

\int\limits^{t_2}_{t_1} {r} \, dt= \int\limits^{2}_{0} ({400+800t-120t^2}) \, dt\\ =(400t+400t^2-40t^3)|^{2}_{0}

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Answer:

120 days

Step-by-step explanation:

Canteen A = 12 days

Canteen B = 8 days

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To find the number of days all 3 canteens will serve food again, find the lowest common multiples of all 3 canteens

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34, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144

Canteen B = 8 days

16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120

Canteen C = 10 days

20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130

The lowest common multiple of 12 days, 8 days and 10 days is 120 days

The next day all 3 canteens will serve soup together again is the next 120 days

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2 years ago
Team members Eric and Natalia secure a grant of $75.00 to buy beams on channels.if the team needs 3 beams at 6 channels,will the
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Step-by-step explanation

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2 years ago
The cross section of rectangular prism A measures 3 units by 2 units. The cross section of triangular prism B has a base that me
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Volume A= one third

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Merle Fonda opened a new savings account. She deposited $40,000 at 10% compounded semiannually. At the start of the fourth year,
IrinaVladis [17]
Use compound interest formula  F=P(1+i)^n twice, one for each deposit and sum the two results.

For the P=$40,000 deposit,
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Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253

For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
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n=2*(6-3), n = 6 
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F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913

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8 0
2 years ago
Polygons ABCD and EFGH are similar. Find the length of EH?
3241004551 [841]

Most likely, polygon <span>ABCD</span> has sides of known lengths.
It is also likely that one of the sides of polygon <span>EFGH</span> (not <span>EH</span>) is also known. For instance, its side <span>EF</span>.

If the above is true, we can find the scaling factor as a ratio between lengths of corresponding sides:
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Since this ratio is constant for any two corresponding lengths,
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From the last two equations we can derive:
<span>EH=AD⋅<span><span>EF</span><span>AB</span></span></span>

Hope That Helped : ) (Took a minute)
5 0
2 years ago
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