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Andrews [41]
2 years ago
7

The flight path of a golf ball is modeled by the function, F (X) = -0.0 2X^2 Plus 6X, we are X represents the horizontal distanc

e and yards the ball has traveled in the air, and F (X) represents the height of the ball. What is appropriate dumm Plus 6 X, we are X represents the horizontal distance in yards the ball has traveled in the air, and F (X) represents the height of the ball. What is appropriate domain?

Mathematics
1 answer:
umka2103 [35]2 years ago
3 0
Let's solve this problem. We know the equation of <span>the height of the ball that is:

</span>f(x)=-0.02x^{2}+6x
<span>
Where x represents </span><span>the horizontal distance in yards the ball has traveled in the air. We know that a distance is always positive, so we conclude that x must be greater or equal than 0, so:

</span>x \geq 0<span>

The horizontal plane represents the zero of the function, given that there is no possibility for the ball to get negative values, then f(x) is also positive. Finally, from the graph, the appropriate domain is:

</span>\boxed{0 \leq x \leq 300}<span>
</span><span>
</span>

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In ΔPQR, p = 220 inches, q = 890 inches and ∠R=121°. Find the length of r, to the nearest inch.
Veronika [31]

Answer:

1021

Step-by-step explanation:

delta math said it was right

6 0
1 year ago
A football field is 120 yards long by 53 yards wide if a player runs diagonally from one corner to the opposite corner. How far
qaws [65]

Answer: They will travel about 131.18 yards.

Step-by-step explanation:

Given : A football field is 120 yards long by 53 yards wide.

We know that a football field is rectangular in shape.

Each interior angle in a rectangle is a right angle.

Then, by Pythagoras theorem, we have

(Diagonal)² = (Length)² + (Width)²

If a player runs diagonally from one corner to the opposite corner, then the length of the diagonal is given by :-

(\text{Diagonal})=\sqrt{(120)^2+(53)^2}\\\\\Rightarrow\ (\text{Diagonal})=\sqrt{14400+2809}\\\\\Rightarrow\ (\text{Diagonal})=\sqrt{17209}\\\\\Rightarrow\ (\text{Diagonal})=131.183078177\approx131.18\text{ yards}

Hence, they will travel about 131.18 yards.

7 0
1 year ago
F (7-3)2 x 7x+4 = 77, find the value of x.
bearhunter [10]

Answer: If I am correct the value of x might be f=0

Step-by-step explanation:

5 0
2 years ago
Water has a density of 1.0 g/cm3. What is the mass of 10.0 cm3 of water?
fgiga [73]
1.0g/cm3 means that the mass of one cm3 is 1.0g
The easiest method to use is the rule of three, and let x be the mass of 10.0 cm3 of water
1g -- > 1.0 cm3
x --> 10.0 cm3

x= (10*1)/1
x=10.0 g

So the mass of 10.0 cm3 of water is 10.0g

Hope this Helps! :)
8 0
2 years ago
Read 2 more answers
The manufacturer of hardness testing equipment uses steel-ball indenters to penetrate metal that is being tested, however, the m
masha68 [24]

Answer:

1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789  

1.667+2.31\frac{1.803}{\sqrt{9}}=3.055  

So on this case the 95% confidence interval would be given by (0.2789;3.055)  

The 95% confidence interval to judge whether the two indeners result in different measurements is?

Yes the confidence interval not contains the value 0 so we can conclude that the values for Diamond are significantly higher than the values for Steel Ball at 5% of significance.

Step-by-step explanation:

We have the following dataset:

specimen    1     2    3     4      5     6     7    8     9

Steel Ball   51   57   61   70   68   54   65  51   53

Diamond   53   55  63   74   69   56   68  51   56

If we calculate the differences diamond-steel ball we have this datase:

d: 2, -2, 2, 4, 1, 2, 3, 0, 3

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=1.667

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =1.803

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=9-1=8  

Since the confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that t_{\alpha/2}=2.31.

Now we have everything in order to replace into formula (1):  

1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789  

1.667+2.31\frac{1.803}{\sqrt{9}}=3.055  

So on this case the 95% confidence interval would be given by (0.2789;3.055)  

The 95% confidence interval to judge whether the two indeners result in different measurements is?

Yes the confidence interval not contains the value 0 so we can conclude that the values for Diamond are significantly higher than the values for Steel Ball at 5% of significance.

4 0
2 years ago
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