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2 years ago

If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?

Mathematics

2 answers:

Volgvan2 years ago

8 0

Answer:

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are $c(x) = \frac{5}{x - 2}$ and d(x) = x + 3

So, (cd)(x) = $(\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}$

Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.

Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)

ad-work [718]2 years ago

4 0

Answer:

the answer is b on edg2020

Step-by-step explanation:

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Mike and Ike are experts at pitching horseshoes. 70% of Mike's tosses are ringers. 67% of Ike's tosses are ringers. Suppose Mike

ahrayia [7]

Mike tosses 70%
Ike tosses 67%
Both tosses 50%

Which of the following is closest to the probability that Ike's proportion is ringers is higher than Mike's for those tosses?

P(m) = 70/100
P(i) = 67/100
P(b) = 50/100

= P(b) * P(i)
= 50/100 * 67/100
= 0.335

The correct answer is letter D) 0.3745.

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2 years ago

Which statement is true about the discontinuities of the function f(x)?

Tema [17]

Answer:

There are asymptotes at x = three-halves and x = negative one-third.

Step-by-step explanation:

f(x) = (x + 1)/ (6x^2 - 7x - 3)

= (x + 1)( / (6x^2 + 2x - 9x - 3)

= (x + 1) / (2x(3x + 1) - 3(3x + 1))

= (x + 1) / (2x - 3)(3x + 1)

Now x = 3/2 and x = -1/3 both make te denominator zero so these are both asymptotes.

6 0

2 years ago

Read 2 more answers

Sociologists want to test whether the number of homeless people in a particular urban area is increasing. In 2010, the average n

Kobotan [32]

Answer:

The test statistic value is 15.3.

Step-by-step explanation:

The hypothesis for this test is:

H₀: The average number of homeless people is not increasing, i.e. μ = 42.3.

Hₐ: The average number of homeless people is increasing, i.e. μ > 42.3.

Given:

$\bar x=45.3\\\sigma=6.2\\n=1000$

As the population standard deviation is provided use a single mean z-test for the hypothesis testing.

The test statistic is:

$z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{45.3-42.3}{6.2/\sqrt{1000}}=15.3$

Thus, the test statistic value is 15.3.

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2 years ago

Write 9.054 X 10-6 in standard form.

Kryger [21]

Answer:

0.000009054

Have a nice day!!! :-)

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2 years ago

How long will it take before twenty percent of our 1,000-gram sample of uranium-235 has decayed? [See Section 6.6 Example 13] Th

horsena [70]

Answer:

From what I can see of the problem, you CANNOT solve for the half-life of U 235 AND then solve for the length of time to determine the 20% decay.

U-235 half-life is 704,000,000 years. (Wikipedia)

The elapsed time formula = half-life * [log (Beginning Amount / ending amount) / log 2]

elapsed time = 7.04 x 10^8 * [log (100 % / 80%) / log 2]

elapsed time =7.04 x 10^8 * [log (1.25) / .30103]

elapsed time =7.04 x 10^8 * [0.096910 / .30103]

elapsed time = 7.04 x 10^8 * 0.321928047

elapsed time = 226,637,000 years

Step-by-step explanation:

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2 years ago