What is the equation of the graph below? On a coordinate plane, a curve goes through (0, 0). It has a maximum of 1 and a minimum
1 answer:
Answer:
y=cos(x+π)
Step-by-step explanation:
Known that the cosine function has a period of 2π.
Now, the parental function is y = cosx, which has y-intercept at y = 1, and x-intercept at π/2.
Notice that the function showed in the graph attached has y-intercept at y = -1 and x-intercept at π/2. This indicates that the function has been moved leftwards π units.
Therefore, the function that belongs to this graph is
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Answer:
The area of the region between the two curves by integration over the x-axis is 9.9 square units.
Step-by-step explanation:
This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:
Given that resulting expression is a second order polynomial of the form , there are two real and distinct solutions. Roots of the expression are:
and
.
Now, it is also required to determine which part of the interval is equal to a number greater than zero (positive). That is:
and
.
Therefore, exists two sub-intervals: and
. Besides,
in each sub-interval. The definite integral of the region between the two curves over the x-axis is:
The area of the region between the two curves by integration over the x-axis is 9.9 square units.
