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creativ13 [48]
1 year ago
13

The two lines graph below are not parallel how many solutions are there to the system of equations

Mathematics
2 answers:
kicyunya [14]1 year ago
6 0
It's out of B, D. I did this last year, but it's definitely out of those two choices.
Elden [556K]1 year ago
3 0
<h2>Answer:</h2>

Option: C is the correct answer.

                   C.  One

<h2>Step-by-step explanation:</h2>
  • We know that if two lines are parallel then the number of solution to the system of equality is zero.
  • If two lines overlap then there are infinite number of solutions.
  • and if two lines intersect at a point then there is a unique solution to the system of equality i.e. one solution.

Based on the graph we observe that the two lines intersect at just one point.

Hence, the number of solutions  to the system of equations is:

                    C.   One

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5 times the amount pretty sure
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27 students are learning to make balloon animals. There are 172 balloons to be shared equally among the students
bija089 [108]
A.) .4 of a balloon is left
To Check:
what I did was divide 172 by 27 and it is 6.37 rounded to ........6 is an equal number so I kept it and .4 will be left over after sharing equally.

B.) 17 more balloons are needs
To Check:
what I was multiply 27 by 7 because each student needs seven balloons and I got 189 after that I subtracted 172 from 189 (189-172=17)
to see how many more balloons are needed.
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1 year ago
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The marketing manager of a branch office of a local telephone operating company wants to study the characteristics of residentia
charle [14.2K]

Answer:

No. There is not enough evidence to support the claim that the population standard deviation is different from $12.

Step-by-step explanation:

The null hypothesis is that the true standard deviation is 12.

The alternative hypothesis is that the true standard deviation differs from 12.

We can state:

H_0: \sigma=12\\\\H_a: \sigma\neq12

The significance level is 0.10.

The sample size is n=15, so the degrees of freedom are:

df=n-1=15-1=14

The sample standard deviation is 9.25.

The test statistic is

T=(n-1)(s/\sigma_0)^2=14*(9.25/12)^2=14*0.77^2=14*0.59=8.32

The critical values for rejecting the null hypothesis are:

\chi_{0.025,13}=5.00875\\\\\chi_{0.975,13}=24.7356

As T=8.32 is within the acceptance region (5.01, 24.74), the null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population standard deviation is different from $12.

8 0
1 year ago
At 11:55 p.m., Thomas ties a weight to the minute hand of a clock. The clockwise torque applied by the
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Answer:

  T(t) = 3sin((t-5)π/30)

Step-by-step explanation:

5 minutes after Thomas ties it on, the torque is zero and increasing. So, the sine function is shifted right 5 minutes. The maximum value is 3, so that is the multiplier of the sine function. The period is 60 minutes, so the coefficient of t is (2π/60) = π/30. The function you want is ...

  T(t) = 3sin((t-5)π/30)

7 0
2 years ago
15 Points!
goblinko [34]

Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC =\frac{b}{a-c}

Step-by-step explanation:

According to midpoint formula

If we have points P (x_{1} ,y_{1} ) and Q (x_{2} ,y_{2} )

then the coordinate (x,y) of mid point of line PQ is given by

x=\frac{x_{1} +x_{2} }{2} and y=\frac{y_{1} +y_{2} }{2}

now from the given diagram A is the mid point of line joining  R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

x=\frac{0+2a}{2}= a and y=\frac{0+2b}{2} =b

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

x= \frac{2c+2c}{2} =2c and y=\frac{2d+0}{2} =d

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

If we have points P (x_{1} ,y_{1} ) and Q (x_{2} ,y_{2} )

then the slope of PQ =\frac{y_{2} -y_{1} }{x_{2}-x_{1}  }

hence slope of AD= \frac{0-b }{c-a}

                                 =\frac{-b}{c-a}

                                  =\frac{-b}{-(a-c)}

                                  =\frac{b}{a-c}

and slope of BC  =\frac{d-(b+d)}{2c-(a+c)}

                            =\frac{d-b-d}{2c-a-c}

                             =\frac{-b}{c-a}

                              =\frac{b}{a-c}

so we have

slope of AD and BC =\frac{b}{a-c}

7 0
2 years ago
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