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2 years ago

Which of the following shows the extraneous solution to the logarithmic equation below???

Mathematics

2 answers:

avanturin [10]2 years ago

7 0

Short Answer x = - 6
Remark
You gave the second best answer.

The trick here is not to divide both sides by 2. Solve the problem this way.

log_5(x + 1)^2 = 2 Take the antilog of both sides
(x + 1)^2 = 5^2 Expand the equation
x^2 + 2x + 1 = 25 Subtract 25 from both sides.
x^2 + 2x - 24 = 0 Factor
(x + 6)(x - 4) = 0 Find the zeros.

x + 6 = 0
x = - 6 <<<<<<<< Answer. This is the extraneous root.
The reason this is an extraneous root is that x<=0 do not have a logarithem

x - 4 = 0
x = 4 This is a legitimate result to the original equation.

Romashka-Z-Leto [24]2 years ago

5 0

Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer: $(15.263,\ 17.537)$

Step-by-step explanation:

According to the given information, we have

Sample size : n= 50

$\overline{x}=16.40$

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Since population standard deviation is unknown, so we use t-test.

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Area=πr^2

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subsitute
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divide 36π by 8
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